Question

Tall pea plants are dominant over short pea plants. If there are 200 short plants in the F2 generation from a cross that followed Mendel’s methods, about how many plants will be tall in that generation? 200 300 600 1,000

Answer 1

Answer:

600

Explanation:

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Answer 2

Answer:

There will be 600 tall plants in that generation.

Explanation:

In Mendel’s cross the selected parents are a tall pea plant and a short pea plant. Both the parents are homozygous. The recessive trait is short. Letter T represents tall and t represents short. Hence the phenotype TT is homozygous dominant and tt is homozygous recessive.

The genotype Tt represents tall since T is dominant over t. Mendel’s cross can be represented as

$Tall \times Short$

$TT \times tt$

F1 generation      Tt     Tt   Tt   Tt

F2 generation     TT   Tt  Tt  tt

In the F1 generation all the plants are tall and in the F2 generation 3/4 plants are tall and1/4 plants are short.

In the question it is given that 200 plants are short in the F2 generation. Let total number of offspring in the F2 generation is x.

$1/4 \times x=200$

x=800

number of tall plants = $3/4 \times x$

$= 3/4 \times 800 =600$

Hence there will be 600 tall plants in the F2 generation.