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laiz [17]
4 years ago
6

Roger mows lawns for $15 minus $3 per lawn for gas. find M the number of lawns he needs to mow to make $100?

Mathematics
2 answers:
Annette [7]4 years ago
7 0

Answer:

100÷(15-3)

Step-by-step explanation:

Phantasy [73]4 years ago
5 0

Answer:

$made=12xnumber of lawns

Step-by-step explanation:

15-3=12

100 divided by 12 =8.3 recurring

8.3 lawns is not possible so round up to 9

$made=12xnumber of lawns

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Which type of geometry best describes the following statement?
sineoko [7]

Answer:

B=hyperbolic geometry

3 0
2 years ago
I will mark the best answer as brainliest.
olga nikolaevna [1]

Step-by-step explanation:

use the pythagoras theory.

a2 + b2 = c2

the firth one use this formula

a2 = c2 - b2

a2 = 10.6² - 5.6²

a2 = 112.36 - 31.36

a2 = 81

a = 9

The same method use to the eighth one

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!
Elanso [62]

Answer:

i think its x

Step-by-step explanation:

6 0
4 years ago
Which angles are supplementary?
Solnce55 [7]

Answer:

∡CFE and ∡BFD, ∡AFB and ∡BFD

Step-by-step explanation:

It is because supplementary angle is straight lines which add ups to 180°

Therefore, ∡CFE and ∡BFD, ∡AFB and ∡BFD are supplementary angles

6 0
3 years ago
An environmentalist wants to find out the fraction of oil tankers that have spills each month. Suppose a sample of 836 tankers i
Alexxandr [17]

Answer:

<em>The 99% confidence interval for the population proportion of oil tankers that have spills each month.</em>

<em>(0.6489 , 0.7311)</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given sample size 'n' = 836

Suppose a sample of 836 tankers is drawn. Of these ships, 577 did not have spills.

sample proportion

                    p^{-}  = \frac{x}{n} = \frac{577}{836} = 0.690

<em>The 99% confidence interval for the population proportion is determined by</em>

<em></em>(p^{-} - Z_{0.01} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.01} \sqrt{\frac{p(1-p)}{n} })<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The Z- value = 2.576</em>

<em></em>(0.690 - 2.576 \sqrt{\frac{0.690(1-0.690)}{836} } , 0.690 + 2.576 \sqrt{\frac{0.690(1-0.690)}{836} })<em></em>

<em>On calculation , we get</em>

<em>(0.690 -  0.0411 , 0.690 + 0.0411)</em>

<em>(0.6489 , 0.7311)</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The 99% confidence interval for the population proportion of oil tankers that have spills each month.</em>

<em>(0.6489 , 0.7311)</em>

<em></em>

<em></em>

8 0
4 years ago
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