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masya89 [10]
3 years ago
13

Mary has some trading cards. Julie has 3 times as many trading cards as Mary. They have 36 trading cards in all. Which of these

equations represents their trading card collection? A) 3x=36 B)x+3=36. C)X+3x=36 D)3x+36=x
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

C. X+3x=36

Step-by-step explanation:

1. If you add the x's to get: 4x=36

2. Do division to get 9.

3. if you plug in 9 in the original,and multiply: 9+27=36

4. There's your answer..... and i ran out of steps.

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The Height of a ramp is 11 inches and the length of its slanted side it 61 inches. What is the length of the base of the ramp?
o-na [289]

Triangle:

39 degrees, 33 degrees, 108 degrees

Side opposite the 108 degrees is 360 feet.

length asked for is d

Hope this helped you! Brainliest? :)

5 0
3 years ago
Evaluate 19C1 PLEASE HELP
LiRa [457]

Answer:

{19}C_1=19

Step-by-step explanation:

We need to find the value of {19}C_1.

C stands for combination.

The formula of combination is as follows :

nC_r=\dfrac{n!}{r!(n-r)!}

Here,

n = 19 and r = 1

So,

nC_r=\dfrac{19!}{1!(19-1)!}\\\\nC_r=\dfrac{19!}{1!\times 18!}\\\\nC_r=\dfrac{19\times 18!}{1!\times 18!}\\\\nC_r=19

So, the value of {19}C_1 is 19.

5 0
3 years ago
Read 2 more answers
Please help my 10 year old nephew...
trasher [3.6K]

After, thorough research I believe that there are 265 pine trees and 0 elm trees since decidous and semi-decidous do not grow near conifers.

4 0
3 years ago
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
3/7 of 8th graders play sports. is 3/5 of the 8th graders that play sports are boys, what fraction of the 8th graders are boys
Svetach [21]

Answer:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

Step-by-step explanation:

Let total number of 8th graders = x

Given that, \frac{3}{7} of 8th graders play sports

\Rightarrow 8th graders who play sports = \frac{3}{7} \times x

Also, Given that, \frac{3}{5} of 8th graders that play sports are boys

Number of 8th graders that play sports, and are boys = \frac{3}{5} \times \text{Number of 8th graders who play sports}

\Rightarrow \dfrac{3}{5} \times \dfrac{3}{7} \times x\\\Rightarrow \dfrac{9}{35} \times x

Hence, the answer is:

\dfrac{9}{35} is the fraction of 8th graders who are boys.

6 0
3 years ago
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