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3 years ago

A bag contains 15 marbles. The probability of randomly selecting a green marble is 1/5. The probability of randomly

Mathematics

1 answer:

meriva3 years ago

3 0

Answer:

Step-by-step explanation:

well if you get all of the fractions into percentage form they will be 20%for green 8% for blue so in turn it would mean 8% of 15 is 2

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LCD of 7/15 and 1/10

forsale [732]

Answer:

Step-by-step explanation:

15 and 10 are multiples of 5

5 x 2 and 5 x 3

LCD means lowest common denominator or the most simplified denominator

7 0

4 years ago

Read 2 more answers

20 ounces to 25 ounces find the percent of change

Gemiola [76]

20% 25-20 equals 5. 5 divided by 20 equals .2 or 20%

7 0

3 years ago

Read 2 more answers

Which is true about the polynomial –3xy2 + 5x?y?

marta [7]

It is a binomial with degree 3

Explanation:

It has two terms: (−3xy2) and (5x2y) → it is a binomial

The degree of an expression is the largest sum of exponents of variables for any term in the expression.

−3xy2=−3x1y2 has a sum of exponents of variables =3

5x2y=5x2y1 also has a sum of exponents of variables =3

→ the expression has degree 3

5 0

3 years ago

Kevin ran 4 miles more than steve ran. the sum of their distance is 26 miles. how far did steve run? the domain of the solution

Mamont248 [21]

26-4=22 22 divided by 2=11

(26-4)÷2=S

(22)÷2=11

S=11

4 0

3 years ago

Which system of linear inequalities has the point (3, –2) in its solution set? y less-than negative 3. y less-than-or-equal-to t

xxTIMURxx [149]

Answer:

$y > -3$ and $y \geq \frac{2}{3}x- 4$

Step-by-step explanation:

<u>The complete question is</u>

Which system of linear inequalities has the point (3,-2) in its solution set?

y < -3

y ≤ 2/3x - 4

y > -3

y ≥ 2/3x - 4

y < -3

y ≥ 2/3x - 4

y > -2

y ≤ 2/3x - 4

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<em>Verify each case</em>

Case A) we have

$y < -3$ ----> inequality A

$y \leq \frac{2}{3}x- 4$ ----> inequality B

Substitute the value of x and y of the point (3,-2) in both inequalities and then compare the results

Inequality A

$-2< -3$ ----> is not true

therefore

The ordered pair is not a solution of the system A

Case B) we have

$y > -3$ ----> inequality A

$y \geq \frac{2}{3}x- 4$ ----> inequality B

Substitute the value of x and y of the point (3,-2) in both inequalities and then compare the results

Inequality A

$-2< -3$ ----> is true

Inequality B

$-2 \geq \frac{2}{3} (3)-4$

$-2\geq -2$ ----> is true

therefore

The ordered pair is a solution of the system B

Case C) we have

$y< -3$ ----> inequality A

$y \geq \frac{2}{3}x- 4$ ----> inequality B

Substitute the value of x and y of the point (3,-2) in both inequalities and then compare the results

Inequality A

$-2< -3$ ----> is not true

therefore

The ordered pair is not a solution of the system C

Case D) we have

y > -2 ----> inequality A

$y \leq \frac{2}{3}x- 4$ ----> inequality B

Substitute the value of x and y of the point (3,-2) in both inequalities and then compare the results

Inequality A

$-2> -2$ ----> is not true

therefore

The ordered pair is not a solution of the system D

9 0

3 years ago