Question

Expand the binomial (2x + y2)5. The fourth term in the expansion of the binomial (2x + y2)5 is

Answer 1

Answer:

Expanded form: $32x^{5} + 160x^{4}y + 320x^{3}y^{2} + 320x^{2}y^{3} + 160xy^{4} + 32y^{5}$

Fourth term: 320x^{2}y^{3}

Step-by-step explanation:

The expansion is given by the following rule:

$(nx + my)^{5} = (nx)^{5} + 5(nx^{4})(my) + 10(nx)^{3}(my)^{2} + 10(nx)^{2}(my)^{3} + 5(nx)(my^{4}) + (my)^{5}$

Given this we just need to replace the values such as n = 2 and m = 2 for the binomial shown.

For the fourth term we just need to count after we have the expanded form and then we have our answer.

Answer 2

Thank you for posting your question here at brainly. The fourth term in the expansion of the binomial (2x + y2)5 is equal to 2x5 + 160x4y + 320x3y2 + 320x2y3 + 160xy4 + 32y5. I hope the answer will help you.