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PilotLPTM [1.2K]
3 years ago
7

Please help...

Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0
To do this you have to times the number of fabric by the length of each fabric
so you have 6*5/8=30/8=15/4 or 3.75
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I need help with this please​
Norma-Jean [14]

Step-by-step explanation:

r = 30/2 = 15

circumference = π*30= 94.2

7 0
3 years ago
Teisha is saving for a $3,150 car. If she can save $350 every month, how many months will it take her to save the amount she nee
Bess [88]

Answer:

Hahahaha ewan ko hindi ko alam yan eh sana alam mo (29) hahah

4 0
3 years ago
Read 2 more answers
Factor 3x^2 + 2x -18x - 12
soldier1979 [14.2K]
3x^2+ 2x -18x -12
= (3x^2+ 2x) -(18x+ 12)
= x(3x+ 2) -6(3x+ 2)
= (3x+2)(x-6)

Final answer: (3x+2)(x-6)
5 0
3 years ago
Navin gave his brother 1/5 of his money and her sister 5/8 of the remainder. Navin remained with $12.00 (a) Calculate how much m
MrRa [10]

Answer:

$40

Step-by-step explanation:

Fraction Navin gave his brother = 1/5

Remainder = 1 - 1/5

5/5 - 1/5 = 4/5

Fraction Navin gave his sister = 4/5 x 5/8 = 1/2

total amount Navin gave his siblings :

\frac{1}{5} + \frac{1}{2}

\frac{2 + 5}{10} = \frac{7}{10}

Fraction that remains = 1 - 7/10

10/10 - 7/10 = 3/10

Let a = amount Navin has initially

3/10 x a = 12

a = (12 x 10) / 2  = $40

5 0
3 years ago
You pull a sled across a horizontal frictionless patch of snow. If your pulling force is in the same direction as the sled's dis
nexus9112 [7]

Answer:

The kinetic energy of the sled is  going to increase by 18.75%

Step-by-step explanation:

The work W realized by a Force F is given by:

W=F_x*x

Where x is the displacement and F_x is the component of the force that is parallel to the displacement.

Additionally, the work is equal to the change in the kinetic energy

W=K_f-K_i

If your pulling force is in the same direction as the sled's displacement, we can said that: F=F_x

And if increases the kinetic energy of the sled by 27%, we can said that:

K_f-K_i=0.27K_i

So, we can formulate the following equation:

W=F*x\\W=0.27K_i\\\\F*x=0.27K_i (1)

On the other hand, if the pulling force acted at an angle of 46° above the horizontal, the work is:

W=F_x*x=Fcos(46)*x=F*x*cos(46)   (2)

Then, replacing (1) in (2), we get:

W=F*x*cos(46)=0.27K_i*cos(46) = 0.1875K_i

Finally, the kinetic energy increase by 18.75% because:

W=K_f-K_i\\W=0.1875K_i\\\\K_f-K_i=0.1875K_i

5 0
3 years ago
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