1 2 4 3 6 8 7 14 16? whats the next term in this sequence?

Graphing Exponential Functions In Exercise, sketch the graph of the function.

denis23 [38]

Answer:

The graph of the function $f(x) = (1/2)^2x + 4$ is attached as image below.

Analysis:

We have two intersection points in the graph

The function $f(x) = (1/2)^2x + 4$ intersects the y-axis at points (0,4)

The function $f(x) = (1/2)^2x + 4$ intersects the x-axis at points (-16,0)

f(x) is positive for x>-`16

f(x) is negative for x<-`16

5 0

2 years ago

Rosa works due north of home. Her husband Juan works due east. They leave for work at the same time. By the time Rosa is 7 miles

polet [3.4K]

<span>This is a right triangle problem. c^2 = a^2 + b^2
Let b = 7 mi (Rosa's distance from home)
Let a = the east leg (Juan's distance from home
(a+1) = c (hypotenuse, distance between them)

(a+1)^2 = a^2 + 7^2

FOIL (a+1)(a+1)
a^2 + 2a + 1 = a^2 + 49

Combine like terms
a^2 - a^2 + 2a = 49 - 1
2a = 48
a =

<span>a = 24 mi, Juan's distance from home

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8 0

2 years ago

Type the correct answer in each box. Use numerals instead of words. Consider this expression. (x+5)(x-7) Complete the box to sho

Ne4ueva [31]

In the top right corner is -7x since we multiply the x and -7

In the bottom row, we'll have 5x for the first box and -35 for the second box. Each box is the result of multiplying the outer values.

In the top left corner, the x^2 is from multiplying the two copies of x.

3 0

2 years ago

A ball with mass m kg is thrown upward with initial velocity 28 m/s from the roof of a building 17 m high. Neglect air resistanc

Nutka1998 [239]

a. At its maximum height, the ball has zero vertical velocity, so

$-\left(28\dfrac{\rm m}{\rm s}\right)^2=2(-g)(y_{\rm max}-17\,\mathrm m)$

$\implies y_{\rm max}=57\,\mathrm m$

b. The ball's height in the air $y$ at time $t$ is given according to

$y=17\,\mathrm m+\left(28\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2$

Solve for $t$ when $y=0$ :

$17+28t-4.9t^2=0\implies t\approx6.3\,\mathrm s$

3 0

2 years ago

HELPPP HELP MEH plane intersects a prism parallel to the base of the prism. The cross section is a polygon with eight sides. The

Kobotan [32]

The minimum number of sides that the polygon at the base of the prism must has 4 sides.

<h3>What is a Polygon?</h3>

This refers to the plane figure in geometry that has three or more sides and angles in a finite straight line.

As we know the minimum number of sides a polygon does the base of the polygon have 4 side.

Now, as the plane intersect a prism parallel to base of the prism so the polygon of 5 sides will form then at least the base of the polygon will have 4 sides.

Learn more about polygons here:

brainly.com/question/1592456

#SPJ1

4 0

1 year ago