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I am Lyosha [343]
3 years ago
15

Write the equation of this line in slope intercept form

Mathematics
1 answer:
Nuetrik [128]3 years ago
7 0

Answer:

The answer would be:

y = 2x - 3

Step-by-step explanation:

Slope Inercept - Form:

y = mx + b

[m] being the slope

[b] being the y - intercept

To find the slope, there are mainly two ways, either see howmany squares it goes up by, or choose two points and find the slope with slope formula.

Either way, the slope is still: 2

[m] = 2

Then find the y - intercept.

Y - intercept is basically the point in which crosses on the y - axis, and the point that crosses it is: -3

[b] = -3

Thats how you find y - intercept.

Now, put it into slope intercept form.

y = mx + b

y = 2x - 3

Hope this helps!

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Brut [27]
In order to find any of the info we need we have to find the first derivative of the equation.  If y=-x^2+8x,  then  y'=-2x+8.  We are told to find the slope at point (1, 7).  Using that x value in our derivative will give us the slope of the line at that point.  y' = -(1)^2+8.  So y' = 7.  That's the slope of the line.  Now we will use that slope along with the x and y coordinate in the slope-intercept form of a line to solve for b.  7 = 7(1) + b so b = 0.  Our equation then is y = 7x.  If you graph these in the same window on your calculator, you can see how perfectly that align at the given point.  It's really quite perfect.
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4 years ago
What is the slope-intercept form of linear equations?
lara31 [8.8K]

to get the equation of any straight line, we simply need two points off of it, let's use the points from the picture below.

(\stackrel{x_1}{8}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{12}-\underset{x_1}{8}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{8}) \\\\\\ y-3=\cfrac{1}{2}x-4\implies y=\cfrac{1}{2}x-1

if we already have the slope, and we can see the y-intercept on the table, then we can simply use the slopel-intercept form and plug both of them in.

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \begin{array}{|c|ll} \cline{1-1} slope\\ \cline{1-1} \cfrac{1}{2}\\ \cline{1-1} y-intercept&\\\cline{1-1} (0~~,~~-1)\\ \cline{1-1} \end{array}~\hfill y=\cfrac{1}{2}x-1

6 0
3 years ago
Find the slope of the line that goes through each pair of points. (-1,7) and (5,7)
Georgia [21]

Answer:

0

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-7)/(5-(-1))

m=0/(5+1)

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5 0
3 years ago
Can someone help me with part b on this question please?
Galina-37 [17]

9514 1404 393

Answer:

  12.0 cm

Step-by-step explanation:

The Pythagorean theorem applies:

  (12 cm)² +b² = (17 cm)²

  b² = (289 -144) cm² = 145 cm²

  b = √145 cm ≈ 12.04 cm

  b ≈ 12.0 cm . . . . rounded to 1 decimal place

8 0
3 years ago
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