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Jobisdone [24]
3 years ago
6

Can someone help pls?

Mathematics
1 answer:
Anni [7]3 years ago
8 0

Answer:

Step-by-step explanation:

Let the original width be x

Then the original length = x + 11

Area = x * (x + 11)

If you decrease each side by 7 you get

Area 1 = (x - 7)(x + 4)

So area - area1 =

x (x + 11) -98 = (x - 7)(x + 4)                  Remove the brackets

x^2 + 11x - 98 = x^2 - 7x + 4x - 28      Combine the like terms

x^2 + 11x - 98 = x^2 - 3x - 28              Add 98 to both sides

x^2 + 11x = x^2 - 3x + 70                     Cancel the x^2

11x = -3x + 70                                       Add 3x to both sides

14x = 70                                               Divide by 14

x = 70 / 14

x = 5

=====================

Original conditions

Answer width = 5

Length = 16

If you check this, you will get totally bizarre answers. Don't check it. It gives negative results. You can do this in math, but not in the real world.

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What is the measure of A?<br> (3y + 27)<br> What is the measure of B?<br> (5y - 3)
user100 [1]

Answer:

y=15

Step-by-step explanation:

3y+27=5y-3

27=2y-3

30=2y

y=15

Thats assuming A and B are equal ^

Hope this helps :)

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3 years ago
Help asap<br> Please reward for this problem is 30 points
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-(3/4)+1 7/8 divided by 1/2 =n
VashaNatasha [74]

first off, let's convert the mixed fraction to improper fraction and then proceed, let's notice that by PEMDAS or order of operations, the multiplication is done first, and then any sums.

\stackrel{mixed}{1\frac{7}{8}}\implies \cfrac{1\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{15}{8}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \div \cfrac{1}{2}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \cdot \cfrac{2}{1}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{4} \\\\\\ \cfrac{-3+15}{4}\implies \cfrac{12}{4}\implies 3

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Hey, I'm in honors math, and I need help with this question. Please help as much as you can PLEASE!!!!
Nana76 [90]

Answer:

Step-by-step explanation:

a) Area of shape A= 17 (15z+1)

Area of A = 255z+17

b) Area of shape B

One way to find the solution is to take the area of

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and subtract the two small rectangles

(z*(14-10)) and

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Area of B= [(2z+8)(z+10)] -4z-48

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