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Semenov [28]
3 years ago
9

How do I solve this? (2 *squareroot of 3) ^2

Mathematics
1 answer:
lesya [120]3 years ago
6 0
6. I hope my answer helped you out.

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2<br>Decrease R420 in the ratio 4:7​
Oxana [17]

Step-by-step explanation:

Let the numbers are 4x and 7x. According to the question if each number is increased by 20, the ratio becomes 7 : 9.

Then,

( 4x + 20 ) : ( 7x + 20 ) = 7 : 9

9( 4x + 20 ) = 7( 7x + 20 )

9( 4x ) + 9( 20 ) = 7( 7x ) + 7( 20 )

9( 20 ) - 7( 20 ) = 7( 7x ) - 9( 4x )

2( 20 ) = 49x - 36x

40 = 13 x

40 / 13 = x

Therefore, number are :–

4 x = 4( 40 / 13 ) = 160 / 13

7 x = 7( 40 / 13 ) = 280 / 13

4 0
3 years ago
What is the quotient?
mojhsa [17]

whelp the answer to your question, the one you put up at least is 16.333 going on infinitely or 16 and 1/3

7 0
2 years ago
Read 2 more answers
In the problem 4 x 12 = 48 which numbers are the factors
Volgvan
C 4and 12 are the factors of 48
3 0
3 years ago
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What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)
Xelga [282]

(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}

5 0
3 years ago
Read 2 more answers
Is anyone able to answer this for me? GIVING BRAINLIEST! hurry!
svetoff [14.1K]
Nicoles pattern:

1
5
17
53
161

Ian’s pattern:

0
1
3
7
15

Ordered pair:

(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)



Table 1 -

Sequence 1:

9
11
13
15
17

Sequence 2:

5
8
11
14
17

Ordered pair:

(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)

Table 2 -

Sequence 1:

20
16
12
8
4

Sequence 2:

20
17
14
11
8

Ordered pair:

(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)

Table 3 -

Sequence 1:

1
3
7
15
31

Sequence 2:

40
24
16
12
10

Ordered pair:

(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)
5 0
2 years ago
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