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galina1969 [7]
3 years ago
8

Consider the following simplified algebraic expression. Which could be the original expression?

Mathematics
2 answers:
Phoenix [80]3 years ago
8 0

Answer:

2nd option

Step-by-step explanation:

this is late but in case someone needs it

dem82 [27]3 years ago
6 0

You have to simplify each equation. You can do that by adding similar values to each other:

(the first equation)

8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² -  2y² + 3x - 4

To make it easier, arrange the values around so that similar ones are beside each other:

8x²y + 2x²y + 7x² - x² - 5y² - 2y² + 3x + 3x - 2 - 4

then add the similar values together:

8x²y + 2x²y = 10x²y

7x² - x² = 6x²

- 5y² - 2y² = -7y²

3x + 3x = 6x

(- 2)+ (- 4) = -6

and if you put them together:

10x²y + 6x² - 7y² + 6x - 6

This isn't the answer to the equation, because it's different. So repeat the process with all the other equations until you find one that is identical to the simplified version.

The answer is the second one: 8x²y + 7x² - 5y² + 3x - 2 + 2x²y - x² -  2y² - 3x - 4

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navik [9.2K]

Answer:

Given information: WY=ZX, A is the midpoint of WY and A is the midpoint of ZX.

To prove :  WA =ZA

Proof:

A is the midpoint of WY, it means A divides WY in two equal parts.

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So, WY is twice of WA.

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ZA=AX

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Substitute the values from equation (1) and (2).

2WA=2ZA

Divide both sides by 2.

WA=ZA

Hence proved.

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