Maggie's brother is 3 years younger than four times her age. The sum of their ages is 27.

An elevator can hold a maximum of 1500 pounds. An average child weighs 75 pounds and the average adult weighs 150 pounds. The el

CaHeK987 [17]

Let's take this problem step-by-step:

Let's first set up some variables:

c: # of children
a: # of adults

Let's examine the information given:

Elevator can hold a maximum of 1500 pounds

⇒ average child is 75 pounds

⇒ average adult is 150 pounds

⇒ therefore: $75c + 150a\leq 1500$

Elevator can fit no more than 14 people

⇒ therefore: $c + a \leq 14$

Let's graph the equations:

$75c+150a\leq 1500\\c+a\leq 14$

⇒ look at the image attached

The point at which the two graphs intersect:

⇒ is the solution that represents the amount of children and adults and

their combine weight

With the horizontal axis being the # of children and vertical axis being the # of adults:

⇒ the solution is 8 children and 6 adults

Answer: 8 children and 6 adults

Hope that helped!

7 0

2 years ago

What is 5a(-3b)(2a^2b^3) simplified?

Anna007 [38]

Simplifying $5a(-3b)(2a^2b^3)$ we get $=-30a^3b^4$

Step-by-step explanation:

We need to simplify $5a(-3b)(2a^2b^3)$

Basically, we need to find the product of all terms.

Finding product:

Using exponent rule: $a^b(a^c)=a^{b+c}$

$5a(-3b)(2a^2b^3)$

$=-15ab(2a^2b^3)$

$=-30a^3b^4$

So, simplifying $5a(-3b)(2a^2b^3)$ we get $=-30a^3b^4$

Keywords: Solving Exponents

Learn more about solving exponents at:

#learnwithBrainly

5 0

4 years ago

How do you find the area of a compound shape

omeli [17]

Answer:

Step-by-step explanation:

If I remember you have to multiply the numbers you have and you get the answer.

4 0

4 years ago

In trapezoid $PQRS,$ $\overline{PQ} \parallel \overline{RS}$. Let $X$ be the intersection of diagonals $\overline{PR}$ and $\ove

jeyben [28]

The area of the trapezoidal comes out to be 125 square units.

<h3>What is trapezoidal?</h3>

A four-sided shape called a trapezoid has one pair of parallel sides. It fundamentally resembles a square, rectangle, or parallelogram in two dimensions.

Now, according to the question;

If a trapezoid PQRS of parallel sides PQ & RS has always been divided into 4 triangles by it's own diagonals PR and QS, which intersect at X,

Then, the area for triangle PSX equals which of triangle QRX, as well as the product of triangle PSX but also triangle QRX equals the same of triangle PQX & triangle RSX.

Let area of the triangle PSX is A₁

Let area of the triangle QRX is A₂

Let area of the triangle PQX is A₃

Let area of the triangle RSX is A₄

Then,

A₁ × A₂ = A₃ × A₄

As A₁ = A₂

The,

A₁² = A₃ × A₄

The areas for the triangles;

A₃ = 20 square units

A₄ = 45 square units.

Substitute the values;

A₁² = 20 × 45

= 900

A₁ = 30

Thus, A₁ = A₂ = 30 square units.

The entire area of the trapezium is;

= A₁ + A₂ + A₃ + A₄

= 30 + 30 + 20 + 45

= 125

Therefore, the complete area of the trapezium PQRS is 125 square units.

To know more about the trapezoidal, here

brainly.com/question/1410008

#SPJ4

The correct question is-

In trapezoid PQRS, PQ is parallel to RS. Let X be the intersection of diagonals PR and QS. The area of triangle PQX is 20 and the area of triangle RSX is 45. Find the area of trapezoid PQRS.

4 0

1 year ago

Can someone help me please???!

serg [7]

Answer:

1) Yes, it is a right angle triangle

2)Yes, it is a right angle triangle

3) No, they are not similar.

Step-by-step explanation:

Dimension of triangle A = 48, 55 & 73

Dimension of triangle B = 36, 77 & 85

For any of the triangles to be a right angled one, then;

c = √(a² + b²)

Where a,b & c are side dimensions of a triangle.

Thus;

Triangle A: c = √(48² + 55²)

c = √5329

c = 73

This tallies with what we are given and so it is a right angled triangle.

Triangle B: c = √(36² + 77²)

c = √(7225)

c = 85

Similar to the third side dimension of 85, thus it is true.

For Triangle A & B to be similar, the ratio of the 3 corresponding sides must be in a whole number ratio.

Thus, we have;

48/36 = 1.5

55/77 = 5/7

73/85 = 73/85

Since the ratios are not similar, then we can say that the triangles are not similar.

4 0

3 years ago