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REY [17]
3 years ago
11

Billy graphed the system of linear equations to find an approximate solution.

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0
The final correct answer

(2.2, -1.35) and (2.2, -1.4)

Your welcome!

Also, could I be marked brainliest?
statuscvo [17]3 years ago
4 0

Answer:

(2.2, –1.4)  and (2.2, –1.35)

Step-by-step explanation:

The solution to this system of equations would be the point of intersection of the lines.  This point is a little past 2 on the x-axis and a little below 1 on the y-axis.  The only two points in our choices that fit these criteria are (2.2, –1.4)  and (2.2, –1.35).

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One grain of this sand approximately weighs 6 x 10^-6g.
emmasim [6.3K]

Answer:

  • 1.2×10¹² grains

Step-by-step explanation:

1 grain = 6×10⁻⁶ g

  • 7200 kg =
  • 7200000 g =
  • 7.2×10⁶ g =
  • 7.2×10⁶ ÷ 6×10⁻⁶ =
  • (7.2÷6)×10⁶⁻ ⁽⁻⁶⁾ =
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4 0
2 years ago
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5 0
3 years ago
An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle
omeli [17]

Answer:

\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}

The middle point of the base is placed at point

\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i

The length of the height is the distance between the points 5+9i and 7+3i

\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}

So, the area of the triangle is

A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

4 0
2 years ago
7th grade math help me pleaseeee
timurjin [86]

Answer:

Step-by-step explanation:

its really simple

just use your brain

4/4 makes 1 whole and 12-11=1 we need to convert the fraction into a whole number. So what over 4 makes 11 wholes? just do 4x11=44 and 44/4=11 and 12-11=1 just do the same for the other ones

3 0
3 years ago
Please help. It’s due today
vladimir1956 [14]

Answer:

There's nothing there I believe you forgot to add a link just add or create another question and i'll see what I can do :)

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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