Answer:
Fill the gaps in this sequence:
25 36 <u>49</u> 64 81 <u>100</u>
This sequence is the numbers 5, 6, 7, 8, 9, and 10 squared.
Work out the cube root of 343, then square it.
<u>49</u>
Since 7 cubed equals 343, then 7 squared is 49.
When you subtract one square number from another the answer is 7.
What are the two square numbers?
<u>16</u> and <u>9</u>
These are the only squares that fit the criteria.
Write down a number you can square to give an answer bigger than 200 but smaller than 300.
<u>15, 16, 17</u>
All of those answers work. 15² is 225, 16² is 256, and 17² is 289. You can choose any of them to enter in and it should work.
Answer:
13.8%
Step-by-step explanation:
P = nCr pʳ qⁿ⁻ʳ
P = ₉C₅ (0.37)⁵ (1−0.37)⁹⁻⁵
P ≈ 0.138
The angle bisector, median, and altitude are all the same things in an isosceles triangle.
That means that the legs of the smaller triangles created by the altitude are 4 root 2.
By special properties of an right triangle, the hypotenuse is 8.
Since the legs of the original right triangle are congruent, the area of the original triangle is 8*8/2.
Now we just simplify:
8*8/2=64/2=32
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75
The angle is α = arccos(-0.8) ≈ 143.13°
______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.
Answer:
36
Step-by-step explanation:
Since E is the midpoint, AE and EB are equal. We can write this as such,
4x+6=10x-12 if we solve from here we get 6x=18. Simplify to get x=3. sub in three for x in the AE equation, 4(3)+6 and solve. You'd get 18 as your answer. Double that to get the solution since AE= 1/2AB. 18*2= 36
AB=36
