Answer:
the factors of x^3-1 are 
Step-by-step explanation:
We need to find factors of x^3 -1
So, the factors of x^3-1 are
Answer:
please mark me as brainlist please
Step-by-step explanation:
we know, ∠BGA = 90
In right angled triangle BGA
AB = 12 cm (diameter of circle)
⇒ (AB)2 = (AG)2 + (BG)2
⇒ 122 = 82 + (BG)2
⇒ BG = 4√5
In right angled triangle BCG
Let CG be x cm.
⇒ (BC)2 = (CG)2 + (BG)2
⇒ (BC)2 = x2 + (4√5)2 ----(1)
As we know,
⇒ (BC)2 = CG × CA ----(2)
From equation (1) and equation (2)
⇒ x2 + (4√5)2 = x × (x + 8)
⇒ x2 + (4√5)2 = x2 + 8x
⇒ 8x = 80
⇒ x = 10 cm
From equation (2)
⇒ (BC)2 = CG × CA
⇒ (BC)2 = 10 × 18 = 180
⇒ BC = √180 = 6√5
6 × 5 = 30
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Answer:
-1
Step-by-step explanation:
The slope formula works nicely for this.
m = (y2 -y1)/(x2 -x1)
m = (-1 -4)/(4 -(-1)) = -5/5 = -1
The slope of the line between the given points is -1.
Answer:
19952 :)
Step-by-step explanation:
