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amid [387]
2 years ago
6

At what rate of interest whould rs 1800 amount to 2500 in 2 years

Mathematics
1 answer:
Trava [24]2 years ago
7 0
A = P(1+r)^t
A = amount made after the specified time
P = original amount of money
r = rate
t = time

2500 = 1800 (1 + r)^2
2500/1800=(1800(1+r)^2)/1800
1.3888 = (1+r)^2
1.17851 = (1 +r)
1.17851 - 1 = r
Rate = .17851
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A manufacturer has 6,305 yards of material to make
docker41 [41]

Answer:

Step-by-step explanation:

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3 years ago
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Help asap pls and thx
vazorg [7]

Step-by-step explanation:

from what I can see there are 2 options to make the 2 triangles congruent :

either the opposite sides must be equal or the neighboring sides must be equal.

so, either

5x = 3x + 10

and

5x - 2 = 4x + 3

or

5x = 4x + 3

and

5x - 2 = 3x + 10

for the first

5x = 3x + 10

2x = 10

x = 5

control

5x - 2 = 4w + 3

5×5 - 2 = 4×5 + 3

23 = 23

correct.

for the second

5x = 4x + 3

x = 3

control

5×3 - 2 = 3×3 + 10

15 - 2 = 9 + 10

13 = 19

no, not a valid solution.

so, x = 5

5 0
2 years ago
The equation of the line that is parallel<br> to 4x+2 and passing through (5,15)
Mila [183]

Answer:

y=4x-5.

Step-by-step explanation:

slop-interception form of the required line is y=kx+b, where k - slop, b - intercept;

1) to find value of k:

if the required line is parallel to the given line, then slop of the given line = slop of the required line, it means k=4 and the required line is y=4x+b;

2) to find the value of 'b':

if to substitute the given coordinates into the equation of the given line, then:

15=4*5+b, b= -5.

3) finally, y=4x-5

8 0
2 years ago
What properties would you use to find the answer 345+130?
kondaur [170]
Addition property of equality
6 0
3 years ago
At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d
Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding  number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

\frac{y+x+x+60+x/2}{4}  = 315

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400  ------------equation (1)</em>

Adding  number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

\frac{y+x+60+x/2}{3}  = 320

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3   => 6y +15x = 7200

(2y+3x = 1800) *-5      =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are  450 there at the farm.</h3>


7 0
3 years ago
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