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Alla [95]
3 years ago
5

Which is NOT a major expense category? housing transportation electricity food

Mathematics
2 answers:
DIA [1.3K]3 years ago
7 0
<span>Housing is definitely a major expense. Whether you rent or own it is likely to be your largest expense. Electricity and food are absolute necessities. Food is somewhat controllable depending on how often you eat out and the types of groceries you purchase. Electricity is also somewhat controllable depending on your lifestyle and how you manage consumption. However both of these categories are still going to comprise a significant portion of your monthly expenses, Transportation, on the other hand, does not have to be a major expense. If you choose not to own a car, walk or bicycle to walk, work from home, use the internet for shopping, ride share, bum rides from friends and use public transportation as a last resort this expense can be very small. However if you choose to own multiple high end cars this expense can also be quite high and greater than food or electricity. In summary, housing, food and electricity are required to survive in the modern world and will always be recurring major expense items. In contrast, it is possible to choose to minimize transportation so it is not a major expense. Now I write this as someone who owns 4 cars so the best approach is to get an education, work hard and make enough money so you don't have to worry about any of these expenses.</span>
otez555 [7]3 years ago
7 0

The answer is electricity! Just took this test and got it right

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Someone please help will mark as brainliest
Anit [1.1K]

Answer:

Perpendicular(p)=21

base(b)=20

hypotenuse(h)=29

Step-by-step explanation:

Now by using the formula:

cos A=b/h

i.e 20 by 29

5 0
3 years ago
What is the maximum Number of different sizes of faces that a rectangular Prism can have.
telo118 [61]

Answer:

3

Step-by-step explanation:

For a rectangular prism of dimensions L × W × H, pairs of opposite faces will have dimensions ...

  • L × W
  • W × H
  • H × L

These will be three different sets of dimensions if L, W, and H are all different lengths.

7 0
3 years ago
regina bought fruit for her family. she bought 3 1/2 pounds of oranges and 4 and 3/4 pounds of peaches. if she used all bit 1 3/
jeka94
First, you would have to combine 3 1/2 and 4 3/4 pounds. That would be 8 and 1/4 lbs. If she used all but 1 3/8 lbs, you would have to do 8 1/4 minus 1 3/8. That means she used 7 1/8 lbs of fruit. 

The equation would be 3/ 12 + 4 3/4 = 8 1/4 - 1/38 = 7 1/8.
8 0
3 years ago
Read 2 more answers
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
umka21 [38]

Answer:

7

Step-by-step explanation:

the median is the middle value of the list. first off, write the list of numbers in ascending order (small to big)

3, 4, 4, 5, 7, 7, 8, 10, 10, 10

since there are 10 values, there are two middle numbers which are 7 and 7. since they are both 7, the median is 7

4 0
3 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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