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2 years ago

What is 6 1/2 - 2 2/5 - 2 1/2 =

Mathematics

1 answer:

VikaD [51]2 years ago

4 0

Answer:

1 3/5

Step-by-step explanation:

Change to mixed fractions, that'll give:

13/2 - 12/5 - 5/2

Using lcm:

16/10

Change back to mixed fractions:

1 6/10

Lowest term:

1 3/5

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SA = 2tr2 + 2trh

julsineya [31]

Given:

Radius of the cylinder = 5 in

Height of the cylinder = 30 in.

To find:

The surface area of the cylinder.

Solution:

The surface area of the cylinder is:

$SA=2\pi r^2+2\pi rh$

Where, r is the radius and h is the height of the cylinder.

Putting $r=5,h=30,\pi=3.14$ in the above formula, we get

$SA=2(3.14)(5)^2+2(3.14)(5)(30)$

$SA=2(3.14)(25)+942$

$SA=157+942$

$SA=1099
$

Therefore, the surface area of the cylinder is 1099 square inches.

6 0

2 years ago

Jhon is making brownies for 48 of his family members. he can make 16 brownies from one package, and he expects everyone yo eat 2

likoan [24]

He will need 48×2=96 brownies so 96÷16= 6 packages of brownie mix

3 0

3 years ago

A box of pencils is 5 1/4 inches wide. Seven pencils, laid side by side, take up 2 5/8 inches of the width. How many inches of t

Andre45 [30]

Answer: Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

Step-by-step explanation:

Given: Width of pencil box = $5\dfrac14\text{ inches}=\dfrac{21}{4}\text{ inches}$

Width of seven pencils = $2\dfrac58\text{ inches}=\dfrac{16+5}{8}\text{ inches}=\dfrac{21}{8}\text{ inches}$

Width of box is not taken up by pencils = Width of pencil box - Width of seven pencils

$\left \{ {{y=2} \atop {x=2}} \right. \dfrac{21}{4}-\dfrac{21}{8}\\\\=\dfrac{21\times2-21}{8}\\\\=\dfrac{21}{8}\text{ inches}=2\dfrac58\text{ inches}$

Width of box is not taken up by pencils = $2\dfrac58\text{ inches}$

Width of each pencil = (Width of seven pencils ) ÷ 7

$=\dfrac{21}{8}\div7\\\\=\dfrac{21}{8}\times\dfrac17\\\\=\dfrac38\text{ inches}$

Width of each pencil $=\dfrac38\text{ inches}$

3 0

2 years ago

Read 2 more answers

Can someone solve this with steps cause idk how to solve the radicals

IceJOKER [234]

$\bf 343^{\frac{2}{3}}+36^{\frac{1}{2}}-256^{\frac{3}{4}}\qquad \begin{cases}
343=7\cdot 7\cdot 7\\
\qquad 7^3\\
36=6\cdot 6\\
\qquad 6^2\\
256=4\cdot 4\cdot 4\cdot 4\\
\qquad 4^4
\end{cases}\\\\\\ (7^3)^{\frac{2}{3}}+(6^2)^{\frac{1}{2}}-(4^4)^{\frac{3}{4}}
\\\\\\
\sqrt[3]{(7^3)^2}+\sqrt[2]{(6^2)^1}-\sqrt[4]{(4^4)^3}\implies \sqrt[3]{(7^2)^3}+\sqrt[2]{(6^1)^2}-\sqrt[4]{(4^3)^4}
\\\\\\
7^2+6-4^3\implies 49+6-64\implies -9$

to see what you can take out of the radical, you can always do a quick "prime factoring" of the values, that way you can break it in factors to see who is what.

8 0

3 years ago

Due to erosion, a beach is

Olenka [21]

Answer:

17 years

Step-by-step explanation:

do 85 divided by 5

5 0

2 years ago

Read 2 more answers