Answer: A scone costs $2.64, and a large coffee costs $1.92.
Explanation: We can write both scenarios as equations, and write it as a system of equations.
“Luis picked up seven scones and four large coffees. He paid $26.16.”
Let’s express the cost of a scone as x.
Let’s express the cost of a large coffee as y.
The first equation would be 7x + 4y = 26.16.
“Rachel picked up six scones and five large coffees. She paid $25.44.”
Let’s express the cost of a scone as x.
Let’s express the cost of a large coffee as y.
The second equation would be 6x + 5y = 25.44.
The systems of equations is:
7x + 4y = 26.16
6x + 5y = 25.44
Let’s take the first equation and solve for x.
7x + 4y = 26.16
7x = 26.16 - 4y
x = (26.16 - 4y)/7
Let’s substitute x in the second equation for (26.16 - 4y)/7, and solve for y.
6((26.16 - 4y)/7) + 5y = 25.44
Distribute the 6 across 26.16 - 4y in the term 6((26.16 - 4y)/7).
(156.96 - 24y)/7 + 5y = 25.44
Rewrite 5y as 35y/7 so it has a common denominator with (156.96 - 24y)/7.
(156.96 - 24y)/7 + 35y/7 = 25.44
Combine like terms.
(156.96 + 11y)/7 = 25.44
Multiply both sides by 7.
156.96 + 11y = 178.08
Subtract 156.96 from both sides.
11y = 21.12
Divide both sides by 11.
y = 1.92
Substitute y into the first equation.
7x + 4(1.92) = 26.16
Simplify 4(1.92).
7x + 7.68 = 26.16
Subtract 7.68 from both sides.
7x = 18.48
Divide both sides by 7.
x = 2.64
Since x = 2.64, we know that the cost of a scone is $2.64.
Since y = 1.92, we know that the cost of a large coffee is $1.92.
Therefore, a scone costs $2.64, and a large coffee costs $1.92.
Answer:
1/4 times 3.
1/4 of 3.
number of fourths in 3.
Step-by-step explanation:
Divid the amount of treasure boxes found each of the divers by their amount of dives and you will get how many they got on one dive, the one with the highest amount you would choose
1. false
2. 50,00
3. about 250
4. True
5. 0
6. 1/13
7. 0.08
8. 25%
9. 1/3
10. 1/2
I could be wrong on some of these though
That is true. The image is always similar, the size of the figure can change but its shape will not.