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Anon25 [30]
3 years ago
13

A sundae requires 333 ice-cream scoops and 444 strawberries, and a milkshake requires 222 ice-cream scoops and 666 strawberries.

Ramses wants to make sundaes and milkshakes with at most 252525 ice-cream scoops and 373737 strawberries. Let SSS denote the number of sundaes he makes and MMM the number of milkshakes he makes.

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

3x+2y\leq 25 \\4x+6y \leq 37

Step-by-step explanation:

Sunday ice cream :

Ice cream scoops = 3

Strawberries = 4

Milkshake :

Ice cream scoops = 2

Strawberries = 6

Ramses wants to  make sundaes and milkshakes with at  most 25 ice-cream scoops  and 37 strawberries.

Let x be the no. sundaes and y be the no. of milkshakes

So, Equations are :

3x+2y\leq 25 \\4x+6y \leq 37

Now we are supposed to graph the solution

3x+2y\leq 25 --- Blue

4x+6y \leq 37 --- Green

Refer the attached figure

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7 0
3 years ago
There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi
umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has x dollar at the starting of each day.

Let, the cost of each cotton candy bag is y.

Now when she sells a total of 12 bags, she has $128.

x+12y=128  .....(1)

After she sells a total of 20 bags, she has $160.

x+20y=160  ....(2)

Subtract equation 1 from equation 2.

(x+20y)-(x+12y)=160-128

8y=32

y=4

Hence, the cost of each cotton candy bag is $4.

6 0
3 years ago
Simplify the following using PEMDAS: [3−(3⋅3)+33÷3] × 4⋅5/10−2⋅3
kompoz [17]

Answer: 34

Step-by-step explanation:

<u>Given expression</u>

[3 - (3 · 3) + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by parentheses in the bracket</u>

=[3 - 9 + 33 ÷ 3] × 4 · 5 / 10 - 2 · 3

<u>Simplify by multiplication</u>

=[3 - 9 + 33 ÷ 3] × 20 / 10 - 6

<u>Simplify by division</u>

=[3 - 9 + 11] × 10 - 6

<u>Simplify by bracket (addition/subtraction)</u>

=[-6 + 11] × 10 - 6

=[4] × 10 - 6

<u>Simplify by multiplication</u>

=40 - 6

<u>Simplify by subtraction</u>

=\boxed{34}

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
The expedition team plan a final practice run to test the range of their communication equipment. One member travels a distance
podryga [215]

Answer:

We need to sketch the problem first.

Find the size of angle R.

One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.

If se substute 50° of 180 we have

180-50=130°

The distance between the two team members is the missing side.

We know two sides and included angle, so we use the cosine rule.

A2+b2+c2-2bcCosA

= 102+122-(2x10x12xcos130°)

=100+144-(-147.08)

=100+144+147.08

=391.08

A==SQRT391.08

=19.775

19.7km

Step-by-step explanation:

Download docx
4 0
3 years ago
Factor the expression: 12x + 16​
12345 [234]

Answer:

12x+16

~Grouping~

12+16

4(3+4)

~Solution~

4(3+4)

Step-by-step explanation:

Hope that helps!!! :)

6 0
3 years ago
Read 2 more answers
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