How do you find x ????
2 answers:
Remark
You can get an idea of how this should be solved by drawing a diameter from the intersection of the tangent and the circumference of the circle and the center of the circle. When you do this and when you draw an angle from either side of the diarmeter joining the two ends of the diameter to the circumference of the circle you get 90 degrees. See the first diagram on the left.
Now what you want is the chord tangent theorem.
The angle at the intersection of the chord and the the tangent point is one half the size of the arc formed by the endpoints of the chord and the circumference of the circle. See diagram on the right.
step one
Draw a line showing what you are talking about.
Step two
82 * 2 = 164
You can get an idea of how this should be solved by drawing a diameter from the intersection of the tangent and the circumference of the circle and the center of the circle. When you do this and when you draw an angle from either side of the diarmeter joining the two ends of the diameter to the circumference of the circle you get 90 degrees. See the first diagram on the left.
Now what you want is the chord tangent theorem.
The angle at the intersection of the chord and the the tangent point is one half the size of the arc formed by the endpoints of the chord and the circumference of the circle. See diagram on the right.
step one
Draw a line showing what you are talking about.
Step two
82 * 2 = 164
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The system of inequalities is the following:
i) <span>y ≤ –0.75x
ii)</span><span>y ≤ 3x – 2
since </span>
, we can write the system again as
Whenever we are asked to sketch the solution of a system of linear inequalities, we:
1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.
A.
to draw the line
consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which hold.
since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).
In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.
For (x, y)=(1, 1) the inequality
, does not hold because
is not true,
this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.
B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2,
we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.
after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.
for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold
because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.
The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.
the lines intersect at (0.533, -0.4) because:
–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533
for x=0.533, y=3x-2=3(0.533)-2=-0.4
Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants
i) <span>y ≤ –0.75x
ii)</span><span>y ≤ 3x – 2
since </span>
Whenever we are asked to sketch the solution of a system of linear inequalities, we:
1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.
A.
to draw the line
consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which
since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).
In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.
For (x, y)=(1, 1) the inequality
this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.
B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2,
we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.
after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.
for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold
because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.
The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.
the lines intersect at (0.533, -0.4) because:
–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533
for x=0.533, y=3x-2=3(0.533)-2=-0.4
Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants