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wel
3 years ago
13

What is the coefficient of 5(-t) HELPPP

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

-5

Step-by-step explanation:

Here are the steps to take in calculating the correlation coefficient:

Determine your data sets.

Calculate the standardized value for your x variables.

Calculate the standardized value for your y variables.

Multiply and find the sum.

Divide the sum and determine the correlation coefficient.

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Relationship B has a greater rate than Relationship A. This graph represents Relationship A.
zhannawk [14.2K]

Answer:

y = 0.6x

Step-by-step explanation:

Look what happens as we move from point (4, 2) to point (8, 4).  The x coordinate increases by 4 and the y coordinate by 2.  Thus, the slope of the line representing Relationship A is m = rise / run = 2/4, or 0.5.

The only one of the four possible answers that could be correct is y = 0.6x, which has a greater rate (slope) than does the given line (m = 0.5).

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The length of the smaller rectangle at the right is 1 inch less than twice its width. Both the dimensions of the larger rectangle are 2 inches longer than the smaller rectangle.
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Pls help i am on a timer
storchak [24]

Answer:

I think the answer is C - (x+2)^2+1

6 0
3 years ago
Triangle TAB has a perimeter of 40 cm. Could the measures of the sides, as shown, actually represent the measures of the sides o
Arada [10]

Answer:

no the measure of the side as shown actually doesn't represent the measure of the side of the triangle

Step-by-step explanation:

Hope this helps!

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5 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
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