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Dimas [21]
3 years ago
10

How to find Maximum kinetic energy​

Chemistry
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

The equation, which Einstein determined, says (electron's maximum kinetic energy) = (energy of the incident light energy packet) minus (the work function). For the example, the electron's maximum kinetic energy is: 2.99 eV - 2.75 eV = 0.24 eV

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What are the characteristics of Mercury? (Select all that apply.)
Sunny_sXe [5.5K]

Answer:

less gravity, closest to the sun

5 0
3 years ago
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13. Would you expect oxygen to form a cation or anion? How many electrons would it gain or lose? Why?
netineya [11]

Answer: C)Anion, it would gain 2 electrons to satisfy the octet rule.

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration of oxygen with 8 electrons is

O:8:1s^22s^22p^4

The cation is formed by loss of electrons and anions are formed by gain of electrons.  

In order to complete its octet and get stable, it gains 2 electrons and thus would form an anion.

O^{2-}:10:1s^22s^22p^6

7 0
3 years ago
I can be found in the 4th period on the periodic table.
Rainbow [258]

Vanadium (V)

Vanadium is the only one in the 4th period here so

4 0
3 years ago
A sample of a vapor occupies a volume of 500 mL at 65°C. If pressure remains constant, what is the volume of the gas at standard
DedPeter [7]

Answer:

403 mL

Explanation:

First, I will assume that the mole is 1, because you are not specifing this.

Now, with the innitial data, we need to get the pressure:

T = 65+273 = 338 K

V = 500 / 1000 = 0.5 L

Now if:

PV = nRT

Then:

P = nRT/V   and V = nRT/P

Let's calculate the P:

P = 1 * 0.082 * 338 / 0.5 = 55.432 atm

The standard temperature is 0° C or 273 K so, the volume is:

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V = 0.40384 L or simply 403.84 mL

8 0
3 years ago
A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th
grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization =  37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0
3 years ago
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