Answer:
CH₃CH₂CH₂CH₂CH₂OH - E. Alcohol
CH₃CH₂OCH₂CH₃ - F. ether
CH₃CH₂CH₂SH - G. thiol
CH₃COOH - J. Carboxylic acid
CH₃CH(OH)CH₂CH₃ - E. Alcohol
CH₃CH₂CH₂CH₂CHO - A. Aldehyde
CH₃CH₂CH₂COCH₃ - B. Ketone
Explanation:
Currently taking organic chemistry.
Hope this helps. :)
Scandium Z= 21 has an electronic configuration of 1s²2s²2p⁶3s²3p⁶3d¹4s².
This shows that Scandium has 21 electrons with three outermost or valency electrons. It is a d-block elements whose valence electrons are equal to their group number, which is equal to the number of electrons in the valence shell.
Answer:
Explanation:
While trying to write the chemical formula for a compound (a neutral molecule), one must identify and exchange the charge of the cation with that of the anion to become the subscript of one other. For example
Aluminium oxide has Aluminium (Al) and oxygen (O); since Al has a charge of 3+ (the cation) and O has a charge of 2- (the anion), the compound would have it's charges as Al³⁺O²⁻ and when the charges are exchanged to there subscripts, it would form Al₂O₃; thus there would be two cations of aluminium for every three anions of oxygen in order to have a neutral molecule.
This same explanation can be given to Aluminium sulfite. Aluminium sulfite has Aluminium (Al) and sulfite (SO₃). Al has a charge of 3+ (cation) while sulfite has a charge of 2- (anion), with the compound having it's charges as Al³⁺(SO₃)²⁻ and when the charges are exchanged to there subscripts, it would form Al₂(SO₃)₃ and would thus have 2 cations of aluminium (Al³⁺) for every 3 anions of sulfite (SO₃³⁻) in order to have a neutral molecule.
Answer:
I believe the first one is correct but I think the second one would be the blood like substance. not a 100% sure sorry
