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An experiment consist of rolling Two fair number cubes. find the probability of each event.

slega [8]

Probability = (number of possible successes) / (number of total possibilities).

<u>Number of total possibilities:</u>
Each cube can come up in 6 different ways.
Total number of possibilities = 6 x 6 = 36

<u>Possible successes:</u>
There are 2 different ways to roll a 3 . . .

1 . . . 2
or
2 . . . 1

The probability is 3/36 = 1/12 = 0.0833... = (8 and 1/3) percent

5 0

2 years ago

A 2-column table has 3 rows. The first column is labeled Domain with entries 0, 1, 2. The second column is labeled Range with en

skad [1K]

Answer:

Step-by-step explanation:

18 - I took the test on edg.

8 0

2 years ago

Read 2 more answers

A multiple-choice test contains 10 questions. There are four possible answers for each question. a) In how many ways can a stude

AnnZ [28]

Answer :

<h3> $4^{10}$ <u> =1048576 ways </u> a student can answer the questions on the test if the student answers every question.</h3>

Step-by-step explanation:

Given that a multiple-choice test contains 10 questions and there are 4 possible answers for each question.

∴ Answers=4 options for each question.

<h3>To find how many ways a student can answer the given questions on the test if the student answers every question :</h3>

Solving this by product rule

Product rule :

<u>If one event can occur in m ways and a second event occur in n ways, the number of ways of two events can occur in sequence is then m.n</u>

From the given the event of choosing the answer of each question having 4 options is given by

The 1st event of picking the answer of the 1st question=4 ,

2nd event of picking the answer of the 2nd question=4 ,

3rd event of picking the answer of the 3rd question=4

,....,

10th event of picking the answer of the 10th question=4.

It can be written as by using the product rule

$=4.4.4.4.4.4.4.4.4.4$

$=4^{10}$

$=1048576$

<h3>∴ there are 1048576 ways a student can answer the questions on the test if the student answers every question.</h3>

3 0

2 years ago

What is a correct congruence statement for the triangles shown? Enter your answer in the box. △QDJ≅△ A triangle Q D J. The b

almond37 [142]

Answer: The correct congruence statement is $\triangle QDJ\cong \triangle MCW$ .

Explanation:

It is given that A triangle Q D J. The base D J is horizontal and side Q D is vertical. Another triangle M C W is made. The base C W and side M C are neither horizontal nor vertical. Triangle M C W is to the right of triangle Q D J.

The sides Q D and M C are labeled with a single tick mark. The sides D J and C W are labeled with a double tick mark. The sides Q J and M W are labeled with a triple tick mark.

Draw two triangles according to the given information.

From the figure it is noticed that

$QD\cong MC$