the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
Step-by-step explanation:
Since the two triangles are similar, you can use proportions to solve for the value of 
Now, just multiply 4 and 12.
Then divide that by 3.
Therefore, 
.
Given the function, <em>f(x) = 3x + 6,</em> we can solve for f(a), f(a + h) and 
by substituting their values into f(x) = 3x + 6. We will have the following:
<em><u>Given:</u></em>
<em>We are told to find:</em>
- f(a)
- f(a + h), and
1. <em><u>Find f(a):</u></em>
- Substitute x = a into f(x) = 3x + 6
f(a) = 3(a) + 6
f(a) = 3a + 6
<em>2. Find f(a + h):</em>
- Substitute x = a + h into f(x) = 3x + 6
f(a + h) = 3(a + h) + 6
f(a + h) = 3a + 3h + 6
<em>3. Find </em><em>:</em>
- Plug in the values of f(a + h) and f(a) into
Thus:
Therefore, given the function, <em>f(x) = 3x + 6,</em> we can solve for f(a), f(a + h) and by substituting their values into f(x) = 3x + 6. We will have the following:
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