Answer:
Step-by-step explanation:
With reference < H
perpendicular (p) = 12
base (b) = 5
so now
tangent of < H
= p / b
= 12 / 5
hope it helps :)
The square root of 75000 is 273.86
Answer:
Multiply row 2 by-1 and add it to row 3.
Step-by-step explanation:
The given augmented matrix is ![\left[\begin{array}{ccc}3&-21&15\\15&8&15\\-2&-1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-21%2615%5C%5C15%268%2615%5C%5C-2%26-1%263%5Cend%7Barray%7D%5Cright%5D)
The permissible row operations are:
1. Switching rows
2. Multiplying a row by a nonzero constant.
3. Adding/Subtracting two rows
Therefore the correct option is: Multiply row 2 by-1 and add it to row 3.
Your question is a bit unclear, but if you mean which lines are parallel to this one then I have an answer.
1/2*4=2 so this line would be y=2 which means it is a horizontal line. Therefore, any other horizontal line would be parallel to it. So just pick a value for Y to equal and that will be your answer.
ie. y=7
We need to split this shape into different shapes. I am going to split it into 2 rectangles, and one triangle. The first thing I am going to do is the triangle. A triangle has an area of 1/2 b*h. Since 25 is the base of the figure, and 16 is the top portion where the triangle dips, we will subtract 16 from 25 to find the base of the triangle. The base is 9. Now we will find the height using the same method with the 23 and the 14. Our height is 9. 9*9 = 81 * 1/2 = 40.5. The area of our triangle is 40.5.
Next I will move on to the bigger rectangle. I am going to create a line where the 16 cm stops on the right hand side. This makes our base 16 cm and the height 23. 16 * 23 is 368. The area of this rectangle is 368
And now for our final rectangle. The base for this one is the same as the base of our triangle, so it is 9. The height of this one is 14. 9 * 14 =126. The area of this rectangle is 126.
Now we need to add these all together.
368 + 126 + 40.5 = 534.5 cm^2
