30g of sugar is used to make 4 cakes. How much sugar is used to make 7 cakes

Mathematics

2 answers:

tankabanditka [31]3 years ago

4 0

Answer:

52.5

Step-by-step explanation:

well first you want to find the ratio and to do that just do 30 / 4 which is

7.5 so for every 1 cake you need 7.5 grams of sugar

if you plug in 7 it is just 7 * 7.5

7 * 7.5 = 52.5

so it takes 52.5 grams of sugar to make 7 cakes

hope this helps please make brainliest

gulaghasi [49]3 years ago

3 0

Answer:

52.5g of sugar is used to make 7 cakes.

Step-by-step explanation:

I love this topic. <3 This is called Scale factors.

If 30 per 4, then how many per 7? is the question. I can't explain this very well on the computer, but maybe I can with picture.

To get from 4 to 7, multiply by 7/4. I forgot what rule/property this is, but it says that if x*z=y, z = y/x. It is helpful!

So now, the scale of the ratio 4:7 is 7/4. This is the same scale of 30:?. Multiply 30 by 7/4. The answer you get is 52.5. If you are confused, try more scale factor problems, and I suggest looking at Khan Academy. ^_^

Hope I helped!

YOU CAN ALSO DO THIS ANOTHER WAY that does not involve multiplying with fractions. With ratios, ORDER MATTERS. Whatever is mentioned first is x, and whatever is mentioned next is y. In this case, the standard ratio format is x:y. x=sugar and y=cake. Divide the ratio 30:4 by 4. You get 7.5:1 Multiply 1 by 7, because 1, 4, and 7 are the cakes. [You can apply "what you do to one side, you must do to the other" to rations, because ratios are just division problems and fractions too]. You must multiply 7.5 by 7 too. You get 52.5 for sugar. Don't forget units. Your teacher might let is slide, but when you get to higher grades, 52.5 as a number? This will be marked wrong. Express the answer with units, and in this case, 52.5g of sugar.

Hope I helped!

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mixer [17]

1. The x-intercepts are x = 0 and x = 6. You can find these by looking for where the line crosses the x-axis. You can see here that it does so at 0 and 6.

2. The maximum value for this function is looking for the f(x) value at the highest point. In this case, you will see that f(x) at the highest point is 120. This happens at x = 3. Once again, this can be found just by looking for the highest point on the graph.

3. Since that is the absolute highest point, it is also the point where is goes from increasing to decreasing. As a result, we know the increasing interval is x<120 and the decreasing interval is x > 120.

4. Finally, the average rate of change between 3 and 5 is -30. You can find this by determining the amount of change in f(x) and dividing it by the amount of change in x. The basic formula is below.

$\frac{new f(x) - old f(x)}{new x - old x}$