If 16 counters are 4/9 then what is One

1 answer:

3 0

36...

divide your 16 by 4, so that you have 1/9. You then multiply the resulting number(4) by your denominator, 9. 4 times 9 = 36

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Select the correct answer.

DerKrebs [107]

I’m pretty sure the answer is c

8 0

3 years ago

Unit 2 | Lesson 10

tiny-mole [99]

The answer is B. 14(m − 8)

m represent the weight of the boxes that Marco lifted.
d represent the weight of the boxes that Drew lifted.

The boxes that Drew lifted each weighed 8 lb less than the boxes Marco lifted:
d = m - 8

So the weight of one box that Drew lifted is (m - 8). Since he lifted boxes, the total number of pounds Drew lifted is 14(m - 8)

3 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Maru [420]

Parameterize $S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k$

with $0\le u\le1$ and $0\le v\le1$ .

Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv$