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gladu [14]
3 years ago
9

What is 5\6 in decimal form?​

Mathematics
2 answers:
vampirchik [111]3 years ago
4 0

0.83333333333333 hope this help

Gwar [14]3 years ago
4 0
0.833333333333333333 have a good day!
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Solve for y 4.2x - 1.4y = 2.1
NeX [460]
4.2x - 1.4y = 2.1
-1.4y = -4.2x + 2.1
y = (-4.2/-1.4)x + 2.1/-1.4
y = 3x - 1.5 <==
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3 years ago
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HELPPPOPP giving braniliest again and again!!
djyliett [7]

Answer:

6 and 48

Step-by-step explanation:

when t=1, the expression is 6

when t=4, the expression is 48

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2 years ago
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The answers to these questions please
vfiekz [6]

Answer:

Q10 is 13.64 cm3

Q 11 is 221 cm3

Step-by-step explanation:

volume is cross sectional area times height for Q 10

volume is length times width times height for Q 11

5 0
3 years ago
Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
DiKsa [7]

Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Let the first endpoint be represented as (x_{1}, y_{1}, z_{1}) and the second endpoint be (x_{2}, y_{2}, z_{2}).

Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Midpoint = (\frac{3 + 7  }{2}, \frac{-2+12 }{2}, \frac{4 + 4  }{2})

Midpoint = (\frac{10 }{2}, \frac{10}{2}, \frac{8  }{2})\\

Midpoint = (5, 5, 4)

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}

d = \sqrt{16 +196 + 0

d =\sqrt{212}

d = 2\sqrt{53}

This is the diameter

To find the radius, r

From Radius = \frac{Diameter}{2}

Radius = \frac{2\sqrt{53} }{2}

∴ Radius = \sqrt{53}

r = \sqrt{53}

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is (5, 5, 4)

Radius of the sphere is \sqrt{53}

The equation of a sphere of radius r and center (h,k,l) is given by

(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

Hence, the equation of the sphere of radius \sqrt{53} and center (5, 5, 4) is

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = \sqrt{(53} )^{2}

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

This is the standard equation of the sphere

6 0
3 years ago
Plz read and answerrrrrrrrrrr
natulia [17]

Answer:

16.7%.

Step-by-step explanation:

There are initially 24 + 15 + 8 = 47 pencils in the bag.

Take a pencil out of this bag of 47 pencils. 15 out of the 47 pencils blue. Let A represent the event of getting a blue pencil on the first pick. The probability of getting a blue pencil is:

\displaystyle P(A) = \frac{15}{47}.

There are now 47 - 1 = 46 pencils left in the bag. However, given that the first pencil removed from the bag is blue, the number of red pencils in the bag will still be 24. Take another pencil out of this bag of 46 pencils. Let B represent the event of getting a red pencil on the second pick. The possibility that the second pencil is red given that the first pencil is blue will be:

\displaystyle P(B|A) = \frac{24}{46}.

The question is asking for the possibility that the first pencil is blue and the second pencil is red. That is:

\displaystyle P(A\cap B) = P(A) \cdot P(B|A) = \frac{15}{47}\times \frac{24}{46} = 0.166512 \approx 16.7\%.

5 0
3 years ago
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