Ask question

Ask question

All categories

3 years ago

6

Explain why a square can be classified as a rectangle

2 answers:

sergeinik [125]3 years ago

4 0

You know how a puppy is a kind of dog, but not all dogs are puppies? Well, the same thing is true for lots of other categories of things, including squares and rectangles.

mihalych1998 [28]3 years ago

3 0

A rectangle can be tall, thin and short and fat or all the sides can have the same length. A square is a quadrilateral with all four angles right angles and all four sides of the same length.

You might be interested in

The moon is 240,000 from the earth. What is the distance as a whole number multiplied by a power of ten?

Lera25 [3.4K]

24 to the power of 4 24x10x10x10x10 = 240,000 If you thought this answer was helpful, please mark it as brainliest. I would greatly appreciate it!

6 0

3 years ago

Evaluate∣2x+7∣ for x=-4

yanalaym [24]

∣2x+7∣ for x=-4

Use the substitution method

∣2*-4+7∣

Mutiply first then add +7

∣2*-4∣= -8

∣-8+7∣= -1

Whenever there is a negative number for absolute value , the number becomes a + positive number.

∣-1∣= 1

Answer:

1

5 0

3 years ago

How many 2.5" x 6" tiles with it on the backsplash that was 2.5 feet tall and 8 feet long

Dahasolnce [82]

24 cause you can only fit 24 on a backsplah

5 0

3 years ago

Write <br> 39<br> 100<br> as a decimal number

ladessa [460]

39.0 is the decimal for it

7 0

3 years ago

Read 2 more answers

Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p

Alla [95]

Answer:

Part A : D.) $2w + 2(2w+ 1) = 29$

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = $2w+1$

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = $2(2w+1)+2w$

we have given the perimeter, so on substituting the value, we get;

$29=2(2w+1)+2w$

Hence The equation used to find the width is $29=2(2w+1)+2w$ .

Now we solve for 'w'.

Applying distributive property, we get;

$4w+2+2w=29\\\\6w+2=29$

Subtracting both side by '2' we get

$6w+2-2=29-2\\\\6w=27$

Dividing both side by 6 we get;

$\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft$

Width of the sandbox = 4.5 ft

Length of the sandbox = $2w+1=2\times4.5 +1 = 9+1=10\ ft$

Hence Length of the sandbox is 10 feet.

3 0

3 years ago