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Hunter-Best [27]
4 years ago
11

Subtrahend is when you subtract a number from another

Mathematics
1 answer:
aniked [119]4 years ago
4 0

Didn't know if this was a question but if yes it is



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A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks w
elena-14-01-66 [18.8K]
(x,y)
east is an increase in x
west is a decrease in x
north is an increase in y
south is a decrease in y

so
3 east (x+3)
1 block south (y-1)
6 blocks west (x-6)
5 blocks north (y+5)

so in total, x+3-6 and y-1+5
basically x-3 and y+4
minus 3 from  and add 4 to y
(1,-2)
(1-3,-2+4)
(-2,2) is the dropoff point
8 0
4 years ago
Brianna is going to the amusement park, where she has to pay a set price of
Ronch [10]

Im pretty sure the answer is A but if not then it is C

This is bcuz B doesn’t make sense because the graph doesn’t say anything close to 100 rides and D doesn’t make sense either.

Hope this helped.

3 0
3 years ago
Find the values of the variables
ki77a [65]

The values of the variables are k = -6 , w = ± 9 , f = -7

Step-by-step explanation:

To solve these problems we will compare the elements inside the [  ]

[-12 , -w²] = [2k , -81]

[2f , 3] =  [-14 , 3]

That mean:

1. -12 = 2k

2. -w² = -81

3. 2f = -14

∵ 2k = -12

Divide both sides by 2 to find k

∴ k = -6

∵ -w² = -81

Divide both sides by -1

∴ w² = 81

Take √ for both sides

∴ w = ± 9

∵ 2f = -14

Divide bith sides by 2

∴ f = -7

The values of the variables are k = -6 , w = ± 9 , f = -7

Learn more:

You can learn more about simple equation in brainly.com/question/13113987

#LearnwithBrainly

8 0
3 years ago
Which is a point on the circle whose center is (0,0) and whose radius is 5? A. (0,0)
Temka [501]

Answer:

(3,4)

Step-by-step explanation:

x^2+y^2=(5)^2

if you graph it you will see that (3,4) is on the circle

4 0
3 years ago
The dimensions of a rectangle are such that its length is 3 in. more than its width. If the length were doubled and if the width
Kay [80]

Answer:

The length of the rectangle is 11 inch and its width is 8 inch.

Step-by-step explanation:

Given:

Rectangle (R_1) and rectangle (R_2).

Let the width of the rectangle be 'x' inch.

Its length = '(x+3)' inch

Area of the rectangle = (A_1)

⇒A_1 = (x)(x+3)

Now for rectangle (R_2) its width is decreased by 1 inch and length is doubled,the area (A_2) will increased by 66 sq-inch.

So,

A_2=A_1+66

According to the question.

⇒ Area of rectangle (R_2)  with width '(x-1)' and length '2(x+3)'='(2x+6)' .

⇒ A_2=(x-1)(2x+6)

Plugging the values of A_2 in terms of A_1.

⇒ A_1+66= (x-1)(2x+6)

Plugging  A_1 = (x)(x+3) into the equation.

⇒ (x)(x+3)+66=(x-1)(2x+6)

⇒ x^2+3x+66=2x^2+6x-2x-6

⇒ x^2-2x^2+3x-6x+2x+6+66=0

⇒ -x^2-x+72=0

Now using quadratic formula we can find the value of 'x'.

Quadratic formula, (x)= \frac{\pm b+\sqrt{b^2-4ac} }{2a}

x= -9 and x= 8

Discarding the negative value.

Our width  = 'x' = 8 inches.

So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.

7 0
3 years ago
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