(x,y)
east is an increase in x
west is a decrease in x
north is an increase in y
south is a decrease in y
so
3 east (x+3)
1 block south (y-1)
6 blocks west (x-6)
5 blocks north (y+5)
so in total, x+3-6 and y-1+5
basically x-3 and y+4
minus 3 from and add 4 to y
(1,-2)
(1-3,-2+4)
(-2,2) is the dropoff point
Im pretty sure the answer is A but if not then it is C
This is bcuz B doesn’t make sense because the graph doesn’t say anything close to 100 rides and D doesn’t make sense either.
Hope this helped.
The values of the variables are k = -6 , w = ± 9 , f = -7
Step-by-step explanation:
To solve these problems we will compare the elements inside the [ ]
[-12 , -w²] = [2k , -81]
[2f , 3] = [-14 , 3]
That mean:
1. -12 = 2k
2. -w² = -81
3. 2f = -14
∵ 2k = -12
Divide both sides by 2 to find k
∴ k = -6
∵ -w² = -81
Divide both sides by -1
∴ w² = 81
Take √ for both sides
∴ w = ± 9
∵ 2f = -14
Divide bith sides by 2
∴ f = -7
The values of the variables are k = -6 , w = ± 9 , f = -7
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Answer:
(3,4)
Step-by-step explanation:
x^2+y^2=(5)^2
if you graph it you will see that (3,4) is on the circle
Answer:
The length of the rectangle is 11 inch and its width is 8 inch.
Step-by-step explanation:
Given:
Rectangle
and rectangle
.
Let the width of the rectangle be 'x' inch.
Its length = '(x+3)' inch
Area of the rectangle = 
⇒
= 
Now for rectangle
its width is decreased by 1 inch and length is doubled,the area
will increased by 66 sq-inch.
So,
According to the question.
⇒ Area of rectangle
with width '(x-1)' and length '2(x+3)'='(2x+6)' .
⇒ 
Plugging the values of
in terms of
.
⇒ 
Plugging
=
into the equation.
⇒
⇒ 
⇒ 
⇒ 
Now using quadratic formula we can find the value of 'x'.
Quadratic formula, (x)=
x= -9 and x= 8
Discarding the negative value.
Our width = 'x' = 8 inches.
So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.