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Ksivusya [100]
3 years ago
10

Do you convert 100 inches per minute to feet per minute

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
8 0
The answer is 8.33 reoccuring
spin [16.1K]3 years ago
4 0
Your answer would be 8.3333333 feet per minute
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10/m+n<br> m=-2<br> n=-1<br> what is the answer
Nesterboy [21]

negative 3 and one third

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2 years ago
Which equation has the same solution as 4-2(x-5)=x-19
dlinn [17]
So x=11
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4 0
3 years ago
If m∠ADC = 164° and is the angle bisector of ∠ADC, find
zhuklara [117]

Answer: 82

Step-by-step explanation:

We know that ADC is the angle bisector

So BDC and BDA are two equal angles

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8 0
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Shtirlitz [24]

Answer:

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3 0
2 years ago
Mendel crossed peas having round seeds and yellow cotyledons (seed leaves) with peas having wrinkled seeds and green cotyledons.
maw [93]

Answer:

1/16

Step-by-step explanation:

This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.

In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).

The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.

According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.

3 0
3 years ago
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