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Semenov [28]
4 years ago
6

Find the slope of the line.

Mathematics
1 answer:
Mariulka [41]4 years ago
8 0
Gud pic came at least 69 times and ur slope is 3/2
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Helppppppp pleaseeeee!!
julia-pushkina [17]
Increasing: positive slope
Decreasing: negative slope
Constant: zero slope.

Hope this helps pls brainliest
8 0
3 years ago
Read 2 more answers
Prove cos a = 5/13 pls solve it and no link pls..........​
Scorpion4ik [409]

<u>Answer</u> : The demonstration is below :)

Step-by-step explanation :

<u>We use Pythagoras' </u><u>theorem </u><u>:</u>

  • In the triangle ABC we have :

AB² = AC² - BC² = 15² - 9² = 144 = 12²

  • In the triangle ABD we have :

DB² = AD² - AB² = 13² - 12² = 5²

cos(a) = BD/AD = 5/13

3 0
2 years ago
g The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control
Rudiy27

Answer:

0.1426 = 14.26% probability that at least one of the births results in a defect.

Step-by-step explanation:

For each birth, there are only two possible outcomes. Either it results in a defect, or it does not. The probability that a birth results in a defect is independent of any other birth. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC).

This means that p = \frac{1}{33}

A local hospital randomly selects five births.

This means that n = 5

What is the probability that at least one of the births results in a defect?

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(\frac{1}{33})^{0}.(\frac{32}{33})^{5} = 0.8574

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.8574 = 0.1426

0.1426 = 14.26% probability that at least one of the births results in a defect.

4 0
3 years ago
Can someone please help me ASAP??
Kryger [21]
Furbelows diene jfd for dog r ISP so odds ry pick
5 0
3 years ago
You can win a new car in a game show if you can put 4 balls in cups in the right order. The cups are lettered A, B, C, and D and
Marina86 [1]
D goes in C
A goes in D
B goes in A
C goes in B


4 0
3 years ago
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