Answer:
w= a/3-4p
Step-by-step explanation:
3w+4p=a divide 3 on both sides
w+4p= a/3 subtract 4p on both sides
w= a/3-4p w is now isolated
Answer:
The area of the shaded region is: 32.25m^2
Step-by-step explanation:
Given
See attachment for rectangle and semicircles
Required
The shaded region
We have:
--- length of the rectangle
This means that the diameters of the three circles add up to 30m.
So, the diameter of 1 is:
![d = l/3](https://tex.z-dn.net/?f=d%20%3D%20l%2F3)
![d = 30/3](https://tex.z-dn.net/?f=d%20%3D%2030%2F3)
![d = 10](https://tex.z-dn.net/?f=d%20%3D%2010)
The area of one circle is:
![A_1 = \pi * \frac{d^2}{8}](https://tex.z-dn.net/?f=A_1%20%3D%20%5Cpi%20%2A%20%5Cfrac%7Bd%5E2%7D%7B8%7D)
![A_1 = 3.14 * \frac{10^2}{8}](https://tex.z-dn.net/?f=A_1%20%3D%203.14%20%2A%20%5Cfrac%7B10%5E2%7D%7B8%7D)
![A_1 = 3.14 * \frac{100}{8}](https://tex.z-dn.net/?f=A_1%20%3D%203.14%20%2A%20%5Cfrac%7B100%7D%7B8%7D)
![A_1 = 39.25m^2](https://tex.z-dn.net/?f=A_1%20%3D%2039.25m%5E2)
The area of the three circles is:
![A_2 = 3 * A_1](https://tex.z-dn.net/?f=A_2%20%3D%203%20%2A%20A_1)
![A_2 = 3 *39.25m^2](https://tex.z-dn.net/?f=A_2%20%3D%203%20%2A39.25m%5E2)
![A_2 = 117.75m^2](https://tex.z-dn.net/?f=A_2%20%3D%20117.75m%5E2)
The area of the rectangle is:
![A_3 = 30 * r](https://tex.z-dn.net/?f=A_3%20%3D%2030%20%2A%20r)
Where r is the radius of the circle
And
![r =d/2](https://tex.z-dn.net/?f=r%20%3Dd%2F2)
![r =10/2](https://tex.z-dn.net/?f=r%20%3D10%2F2)
![r =5](https://tex.z-dn.net/?f=r%20%3D5)
So, we have:
![A_3 = 30 * r](https://tex.z-dn.net/?f=A_3%20%3D%2030%20%2A%20r)
![A_3 = 30 * 5](https://tex.z-dn.net/?f=A_3%20%3D%2030%20%2A%205)
![A_3 = 150](https://tex.z-dn.net/?f=A_3%20%3D%20150)
So, the shaded region is:
![A_4 = A_3 - A_2](https://tex.z-dn.net/?f=A_4%20%3D%20A_3%20-%20A_2)
![A_4 = 150 - 117.75](https://tex.z-dn.net/?f=A_4%20%3D%20150%20-%20117.75)
![A_4 = 32.25m^2](https://tex.z-dn.net/?f=A_4%20%3D%2032.25m%5E2)
Answer:
x = 10
Step-by-step explanation:
Perimeter of a triangle = the sum of the three sided of the triangle.
In an isosceles triangle, there are two equal sides and a base.
Perimeter = ( 3x - 6) + (3x - 6) + x
58 = 7x - 12
58 + 12 = 7x
70 = 7x
![\frac{70}{7} = \frac{7x}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B70%7D%7B7%7D%20%3D%20%5Cfrac%7B7x%7D%7B7%7D)
10 = x
Answer:
area of the big triangle is QS*RT, where we know the QS
so we need to derive the area of big triange
the big triange is sum of the larger triangle (QT*RT) + smaller one (TS*RT)
so RT*(5+2.2)=RT(5)+RT(2.2)
the rest is simple to solve
Step-by-step explanation:
Answer: -6
-6•-7=42
Negative times a negative equals a positive