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blagie [28]
4 years ago
9

Complete the following statement. (?) x (-7) = 42

Mathematics
2 answers:
MA_775_DIABLO [31]4 years ago
6 0
Answer: -6

-6•-7=42
Negative times a negative equals a positive
djverab [1.8K]4 years ago
5 0
-6 because you need a negative to knock out the negative to make it a positive so you know it’s going to be negative then you figure what 42\7 is and you get six
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What is the additive inverse of the polynomial?<br> -7y^2+x^2y-3xy-7x^
gogolik [260]

The additive inverse of the polynomial - 7{y^2} + {x^2}y - 3xy - 7{x^2} is \boxed{7{y^2} - {x^2}y + 3xy + 7{x^2}{\text{ or }} - \left( { - 7{y^2} + {x^2}y - 3xy - 7{x^2}} \right)}.

Further explanation:

Given:

The polynomial is - 7{x^2} + {x^2}y - 3xy - 7{x^2}.

Explanation:

The given polynomial is - 7{y^2} + {x^2}y - 3xy - 7{x^2}.

The additive inverse can be defined as when we add a number to some number and get result as zero.

The value of additive inverse is same as of the number but the sign of the additive inverse is opposite.

The additive inverse of the polynomial can be expressed as follows,

\begin{aligned}A&= - 7{y^2} + {x^2}y - 3xy - 7{x^2} + \left( {7{y^2} - {x^2} + 3xy + 7{x^2}} \right)\\&= - 7{y^2} + 7{y^2} + {x^2}y - {x^2}y - 3xy + 3xy - 7{x^2} + 7{x^2}\\&= 0\\\end{aligned}

The additive inverse of the polynomial - 7{y^2} + {x^2}y - 3xy - 7{x^2} is \boxed{7{y^2} - {x^2}y + 3xy + 7{x^2}{\text{ or }} - \left( { - 7{y^2} + {x^2}y - 3xy - 7{x^2}} \right)}.

Learn more:

  1. Learn more about inverse of the function brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497.

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Polynomial

Keywords: roots, prime polynomial, linear equation, quadratic equation, zeros, function, polynomial, solution, cubic function, degree of the function.

4 0
3 years ago
Read 2 more answers
Find the value of x, what makes r parallel to s
Pavlova-9 [17]

Answer:

a. x = 14 (see explanation)

b. the arrows along the lines

Step-by-step explanation:

The relationship of these two expressions is Same Side, which means their sum is 180.

<u><em>plugging</em><em> </em><em>in</em></u>

108 + 4x + 16 = 180 | Given

124 + 4x = 180 | Add the numbers

4x = 56 | Subtract 124 from both sides

x = 14 | Divide both sides by 4

3 0
3 years ago
Please help please help
pshichka [43]
Each sentence that has an “as” or “like” is a simile and each that doesn’t is a metaphor. Hope this helps!
5 0
3 years ago
Thirty people attend an event in which 5 are chosen at random to receive door prizes. the prizes are all the same, so the order
Pavel [41]
6 groups of five people
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8 0
3 years ago
Which products result in a difference of squares? Select three options. (x minus y)(y minus x) (6 minus y)(6 minus y) (3 + x z)(
ValentinkaMS [17]

Answer:

Third option: (3 + xz)(-3 + xz)

Fourth option: (y^2 - xy)(y^2 + xy)

Sixth option: (64y^2 + x^2)(-x^2 + 64y^2)

Step-by-step explanation:

By definition, we can factor the Difference between two squares:

a^2 - b^2 = (a+b)(a-b)

In order to find which products results in a difference of squares, we need to check each option:

 1.\ (x - y)(y - x)=(x)(y)+(x)(-x)-(y)(y)+(-y)(-x)=xy-x^2-y^2+xy=-x^2-y^2+2xy

The product does not result in a difference of squares.

2.\ (6 - y)(6 - y)

Since the signs are equal (-), the product will not result in a difference of squares.

Using Distributive Property for the other options, we get:

3.\ (3 + xz)(-3 + xz)=(3)(-3)+(3)(xz)+(xz)(-3)+(xz)(xz)=\\\\=-9+3xz-3xz+x^2z^2=x^2z^2-9=(xz)^2-(3)^2

The product results in a difference of squares.

4.\ (y^2 - xy)(y^2 + xy)=(y^2)(y^2)+(y^2)(xy)-(xy)(y^2)-(xy)(xy)=\\\\=y^4+xy^3-xy^3-x^2y^2=y^4-x^2y^2=(y^2)^2-(xy)^2

The product results in a difference of squares.

5.\ (25x - 7y)(-7y + 25x)=(25x - 7y)(25x - 7y)

Since the signs are equal (-), the product will not result in a difference of squares.

6.\ (64y^2 + x^2)(-x^2 + 64y^2)=(64y^2 + x^2)(64y^2 - x^2)=\\\\=(64y^2)(-x^2)+(64y^2)(64y^2)+(x^2)(-x^2)+(x^2)(64y^2)=\\\\=-64y^2x^2+4096y^4-x^4+64y^2x^2=\\\\=4096y^4-x^4=(64y^2)^2-(x^2)^2

The product results in a difference of squares.

5 0
3 years ago
Read 2 more answers
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