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Leokris [45]
3 years ago
11

Darcy pays $31 for five books Kenneth pays $49.25 for 8 books what are they each paper book are they equivalent ratios

Mathematics
1 answer:
Verizon [17]3 years ago
4 0
Darcy’s books were $6.20 each and Kenneth’s were approximately $6.16 rounded to the nearest hundredth. They are not equivalent ratios
You might be interested in
I need help with my math homework. The questions is: Find all solutions of the equation in the interval [0,2π).
Aleksandr-060686 [28]

Answer:

\frac{7\pi}{24} and \frac{31\pi}{24}

Step-by-step explanation:

\sqrt{3} \tan(x-\frac{\pi}{8})-1=0

Let's first isolate the trig function.

Add 1 one on both sides:

\sqrt{3} \tan(x-\frac{\pi}{8})=1

Divide both sides by \sqrt{3}:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

Now recall \tan(u)=\frac{\sin(u)}{\cos(u)}.

\frac{1}{\sqrt{3}}=\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}

or

\frac{1}{\sqrt{3}}=\frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}}

The first ratio I have can be found using \frac{\pi}{6} in the first rotation of the unit circle.

The second ratio I have can be found using \frac{7\pi}{6} you can see this is on the same line as the \frac{\pi}{6} so you could write \frac{7\pi}{6} as \frac{\pi}{6}+\pi.

So this means the following:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}}

is true when x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

where n is integer.

Integers are the set containing {..,-3,-2,-1,0,1,2,3,...}.

So now we have a linear equation to solve:

x-\frac{\pi}{8}=\frac{\pi}{6}+n \pi

Add \frac{\pi}{8} on both sides:

x=\frac{\pi}{6}+\frac{\pi}{8}+n \pi

Find common denominator between the first two terms on the right.

That is 24.

x=\frac{4\pi}{24}+\frac{3\pi}{24}+n \pi

x=\frac{7\pi}{24}+n \pi (So this is for all the solutions.)

Now I just notice that it said find all the solutions in the interval [0,2\pi).

So if \sqrt{3} \tan(x-\frac{\pi}{8})-1=0 and we let u=x-\frac{\pi}{8}, then solving for x gives us:

u+\frac{\pi}{8}=x ( I just added \frac{\pi}{8} on both sides.)

So recall 0\le x.

Then 0 \le u+\frac{\pi}{8}.

Subtract \frac{\pi}{8} on both sides:

-\frac{\pi}{8}\le u

Simplify:

-\frac{\pi}{8}\le u

-\frac{\pi}{8}\le u

So we want to find solutions to:

\tan(u)=\frac{1}{\sqrt{3}} with the condition:

-\frac{\pi}{8}\le u

That's just at \frac{\pi}{6} and \frac{7\pi}{6}

So now adding \frac{\pi}{8} to both gives us the solutions to:

\tan(x-\frac{\pi}{8})=\frac{1}{\sqrt{3}} in the interval:

0\le x.

The solutions we are looking for are:

\frac{\pi}{6}+\frac{\pi}{8} and \frac{7\pi}{6}+\frac{\pi}{8}

Let's simplifying:

(\frac{1}{6}+\frac{1}{8})\pi and (\frac{7}{6}+\frac{1}{8})\pi

\frac{7}{24}\pi and \frac{31}{24}\pi

\frac{7\pi}{24} and \frac{31\pi}{24}

5 0
3 years ago
Will give 50 points
mafiozo [28]

Answer:

120.96$

Step-by-step explanation:

150$ - 25% = 112$


112$ + 8% = 120.96$


Hope this helps!!

7 0
2 years ago
Write 408,032,009 in expanded form
deff fn [24]
Expanded form means breaking the number into addition.



408,032,009 = 400,000,000 + 8,000,000 + 30,000 + 2,000 + 9
5 0
3 years ago
Read 2 more answers
Is that better is just need help
yawa3891 [41]
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack? 

1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams. 

You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..

4000grams/50snacks = 80 grams each snack.

#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?

215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams 

So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348 
0.348 is the difference.

5 0
3 years ago
Read 2 more answers
3. 'a' and 'b' are the intercepts made
Julli [10]

Given:

'a' and 'b' are the intercepts made  by a straight-line with the co- ordinate axes.

3a = b and the line  pass through the point (1, 3).

To find:

The equation of the line.

Solution:

The intercept form of a line is

\dfrac{x}{a}+\dfrac{y}{b}=1         ...(i)

where, a is x-intercept and b is y-intercept.

We have, 3a=b.

\dfrac{x}{a}+\dfrac{y}{3a}=1           ...(ii)

The line  pass through the point (1, 3). So, putting x=1 and y=3, we get

\dfrac{1}{a}+\dfrac{3}{3a}=1

\dfrac{1}{a}+\dfrac{1}{a}=1

\dfrac{2}{a}=1

Multiply both sides by a.

2=a

The value of a is 2. So, x-intercept is 2.

Putting a=2 in b=3a, we get

b=3(2)

b=6

The value of b is 6. So, y-intercept is 6.

Putting a=2 and b=6 in (i), we get

\dfrac{x}{2}+\dfrac{y}{6}=1

Therefore, the equation of the required line in intercept form is \dfrac{x}{2}+\dfrac{y}{6}=1.

5 0
2 years ago
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