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4 years ago

14m+m+17m−9m if m=30

Mathematics

1 answer:

NikAS [45]4 years ago

4 0

Answer:

690

Step-by-step explanation:

Put 30 where m is in the expression and do the arithmetic. Or, simpify the expression first, then do the same.

14·30 +30 +17·30 -9·30 = 420 +30 +510 -270 = 690

Simplifying first, you have ...

14m +m +17m -9m = m(14 +1 +17 -9) = 23m

23·30 = 690

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Tems11 [23]

Answer:

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3 years ago

In the diagram below, the value of y must be

REY [17]

Answer:

y = 45°

Step-by-step explanation:

4 sides = 360°

(2y+1)° + y° + 112° + 112° = 360°

2y + y = 360 - 112 - 112 - 1

3y = 135

y = 135÷3

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4 0

3 years ago

What slope is perpendicular to m= 5/8 m=-5/8 m=5/8 m=-8/5 m=8/5

MrRa [10]

Answer:

C) $m =\frac{-8}{5}$

The slope of the perpendicular line $m =\frac{-8}{5}$

Step-by-step explanation:

Explanation:-

Given that the slope of the given line is

$m =\frac{5}{8}$

The slope of the perpendicular line

= $\frac{-1}{m}$

The slope of the perpendicular line

= $\frac{-1}{\frac{5}{8} }$

Final answer

The slope of the perpendicular line

$m =\frac{-8}{5}$

7 0

3 years ago

Can someone help me please ASAP?

PtichkaEL [24]

Answer:

the answer is the right because it has the least negative so its 0. the left is -2 which is less then zero.

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP!! (50 POINTS)

Marrrta [24]

Answer:

Since pair of opposite sides are parallel and adjacent sides meets at right angles, the quadrilateral COAT is a rectangle.

Step-by-step explanation:

The vertices of the given quadrilateral is $C(2,0),O(7,0),A(7,2),T(2,2)$

It is sufficient to show that pair of opposite sides are parallel and adjacent sides are perpendicular.

The slope of each side can be found using the formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

Slope of CO,

$M_{CO}=\frac{0-0}{7-2}=\frac{0}{5} =0$

A line with a zero slope is a horizontal line.

The slope of OA,

$M_{OA}=\frac{2-0}{7-7} =\frac{2}{0}$

This slope is undefined.

A line with an undefined slope is a vertical line.

This shows that,the side CO and OA of the quadrilateral meets at right angle.

The slope of AT,

$M_{AT}=\frac{2-2}{7-0}=\frac{0}{5}=0$

This is also a horizontal line.

The slope of TC,

$M_{TC}=\frac{2-0}{2-2} =\frac{2}{0}$

This also a vertical line.

This implies that, side TC and side AT meets at Tat right angles and TC is parallel to OA.

Also AT is parallel to TO.

This shows that COAT is a rectangle.

8 0

3 years ago