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yulyashka [42]
3 years ago
14

The function ggg is given in three equivalent forms. Which form most quickly reveals the vertex? Choose 1 answer: Choose 1 answe

r: (Choice A) A g(x)=\dfrac{1}{2}(x-8)^2-8g(x)= 2 1 ​ (x−8) 2 −8g, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 2, end fraction, left parenthesis, x, minus, 8, right parenthesis, squared, minus, 8 (Choice B) B g(x)=\dfrac{1}{2}(x-12)(x-4)g(x)= 2 1 ​ (x−12)(x−4)g, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 2, end fraction, left parenthesis, x, minus, 12, right parenthesis, left parenthesis, x, minus, 4, right parenthesis (Choice C) C g(x)=\dfrac{1}{2}x^2-8x+24g(x)= 2 1 ​ x 2 −8x+24g, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 2, end fraction, x, squared, minus, 8, x, plus, 24 What is the vertex? Vertex = ((left parenthesis ,,comma ))right parenthesis
Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

(A)g(x)=\dfrac{1}{2}(x-8)^2-8

(h,k)=(8,-8)

Step-by-step explanation:

(A)g(x)=\dfrac{1}{2}(x-8)^2-8\\(B)g(x)=\dfrac{1}{2}(x-12)(x-4)\\(C)g(x)=\dfrac{1}{2}x^2-8x+24

From the given equivalent forms of the function g(x), we are to pick which form quickly reveals the vertex.

The vertex form of a parabola is given: f (x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.

Therefore, Option A, (A)g(x)=\dfrac{1}{2}(x-8)^2-8 quickly reveals the vertex.

From the above, h=8, k=-8. Therefore the vertex (h,k)=(8,-8)

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The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

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3 years ago
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Elan Coil [88]

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3 years ago
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How do you find the slope (m) and the y-intercept for (0,-4), (5,-4)?
navik [9.2K]

Answer:

In order to find the slope (m), and the y-intercept of this coordinate pair, you must complete rise over run.

This is represented by y2-y1, x2-x1. This can be represented like so:

-4-0 = -4

5--4 = 9

Here, we have concluded that our slope is -4/9.

Now, we must convert this into point slope form. Point slope form is y-y1=m(x-x1). This will look like this in our situation:

y+4=-4/9(x-0)

To solve, distribute the -4/9 first, which will leave you with:

y+4=-4/9x+0

Now, subract the 4 to both sides of the equation.

Our final answer looks like: y=-4/9-4.

<em>-</em>

<em>SLOPE: -4/9</em>

<em>Y INTERCEPT: -4 </em>


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