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3 years ago

13

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1 answer:

EleoNora [17]3 years ago

3 0

Answer:

24 inches

Step-by-step explanation:

It is the same because the rotation doesn't change the size of the triangle

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If the circumference of a circle measures 12π cm, what is the area of the circle in terms of π?

frez [133]

So the formula for the circumference of a circle is π x diameter
Since we know the the circumference already, we just divide that by π:

12π / π = 12

Now we halve the diameter to get the radius:
12 / 2 = 6

The area of a circle is π x radius²
So the area is:

·π x 6² = 36π· (or 113 not in terms of π)

5 0

4 years ago

Simplify the following expression:<br> 4x - 3y + 2z - 3x - y + 3z = ?

nordsb [41]

Add all the like terms together so 4x-3x is x or 1x -3y-y is -4y 2z+3z is 5z so put them all together it's x-4y+5z

7 0

3 years ago

Solve for L: A = L ⋅ W ⋅ H (1 point)

butalik [34]

Answer:

L= A/WH

Step-by-step explanation:

Off topic Btw it reminds me of area = length * width/height

7 0

3 years ago

Read 2 more answers

Factor the polynomial

Anettt [7]

Answer:

(3x + 5)(9x^2 - 15x + 25)

Step-by-step explanation:

27x^3 + 125

= (3x)^3 + 5^3

= (3x + 5) ((3x)^2 - (3x)(5) + 5^2)

= (3x + 5)(9x^2 - 15x + 25)

FYI: a³ + b³ = (a + b)(a² – ab + b²)

8 0

2 years ago

Read 2 more answers

The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th

Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = $59^{0}$ + $34^{0}$

= $93^{0}$

Thus,

<CAB = $90^{0}$ - $59^{0}$ = $31^{0}$

<CBA = $90^{0}$ - $34^{0}$ = $56^{0}$

Sine rule states;

$\frac{a}{Sin A}$ = $\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

$\frac{b}{Sin B}$ = $\frac{c}{Sin C}$

$\frac{b}{Sin 56^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{b}{0.8290}$ = $\frac{242}{0.9986}$

cross multiply,

b = $\frac{0.8290*242}{0.9986}$

= 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

$\frac{a}{Sin A}$ = $\frac{c}{Sin C}$

$\frac{a}{Sin 31^{0} }$ = $\frac{242}{Sin 93^{0} }$

$\frac{a}{0.5150}$ = $\frac{242}{0.9986}$

cross multiply,

a = $\frac{0.5150*242}{0.9986}$

= 124.8073

Sarge is about 125 feet away from the fire.

8 0

3 years ago