2/11 because there is 11 letters which would be the denominator and then there is 2 I's which would be the numerator
If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer:
z = -166
Step-by-step explanation:
1. Subtract 3 from both sides to get z/2 = -83
2. Multiply 2 by both sides to get z = -166
z = -166
Answer:
C = (2, 6)
Step-by-step explanation:
The coordinates of point C can be found as the weighted average of the endpoint coordinates. The weights are the reverse of the relative segment lengths.
For AC : CB = 3 : 1, we have ...
C = (A +3B)/(1+3) = ((-1, 0) +3(3, 8))/4 = (-1+9, 0+24)/4
C = (2, 6)
Answer:
IS THERE MORE TO THE PROBLEM? NOT ENOUGH INFORMATION IS GIVEN
Step-by-step explanation:
