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mote1985 [20]
1 year ago
13

For each of the following a) identify the inverse function needed to solve for the indicated angle and b) solve for the angle (r

ound to the nearest tenth of a degree).

Mathematics
1 answer:
Genrish500 [490]1 year ago
5 0

The angle is the cosine inverse function because base over hypotenuse. Then the angle will be 37°.

<h3>What is trigonometry?</h3>

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The triangle with base of 4 units and hypotenuse of 5 units.

We know that the angle is given by the cosine inverse function because base over hypotenuse. Then we have

⇒ cos⁻¹ (4/5)

Then the angle will be

⇒ 36.869 ≈ 37°

More about the trigonometry link is given below.

brainly.com/question/22698523

#SPJ1

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If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

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  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

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