Answer:
a
Step-by-step explanation:
<h3>Proof:</h3>
Refer to the attached figure.
There are a couple of ways you can go at this. One is to show the sums of the marked angles are the same, hence ∠B ≅ ∠D. Instead, we're going to show that ΔABD ≅ ΔCDB, hence ∠A ≅ ∠C.
1. AB║DC and BC║AD . . . . given
2. BD is a transversal to both AB║DC and BC║AD . . . . given
3. ∠CBD ≅ ∠ADB . . . . alternate interior angles where a transversal crosses parallel lines are congruent
4. ∠CDB ≅ ∠ABD . . . . alternate interior angles where a transversal crosses parallel lines are congruent
5. BD ≅ BD . . . . reflexive property of congruence
6. ΔABD ≅ ΔCDB . . . . ASA postulate
7. ∠A ≅ ∠C . . . . CPCTC
∠A and ∠C are opposite angles of parallelogram ABCD, so we have shown what you want to have shown.
Answer:
Both answers are correct, depending on the angle taken as reference
Step-by-step explanation:
we know that
In a right triangle
The slope ratio of the triangle is equal to the function tangent
The function tangent in a right triangle is equal to the opposite side to the angle divided by the adjacent side to the angle
so
-----> Ben's ratio
and
------> Carlissa's ratio
therefore
The slope will depend on the angle taken as a reference
so
Both answers are correct, depending on the angle taken as reference.
Answer:
x=-1, y=6. (-1, 6).
Step-by-step explanation:
x+y=5
x-y=-7
---------
2x=-2
x=-2/2
x=-1
-1+y=5
y=5-(-1)=5+1=6
Answer:
A circle or the circumference on a clock would be 360 degrees, half being 180 degrees, and a quarter being 90 degrees.
Step-by-step explanation:
Hope this helps! :D