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3 years ago

Brainly so you better do it right

Mathematics

2 answers:

alexira [117]3 years ago

8 0

3/32 i did it on my paper then the calculator. please mark me brainliest!!!

kogti [31]3 years ago

3 0

Answer:

Step-by-step explanation:

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In one day and a child five times the sum of the number of hours Brian traveled and 2. Together they traveled 20 hours. Find the

motikmotik

<span>Annie traveled 17 hours and Brian traveled 3 hours. 17+3=20. 3*5=15+2=17.</span>

4 0

3 years ago

Bobby decides to sell lemonade on a hot summer day. If Bobby sells 20 glasses of lemonade for $0.20 per cup, and his average tot

borishaifa [10]

Answer:

Bobby's economic profits for the day is $0.60.

Step-by-step explanation:

Bobby sells 20 glasses of lemonade for $0.20 per cup.

Amount earned = $20\times0.20=4$ dollars

The average total cost is $0.17.

So, difference in selling amount and average = $0.20-0.17=0.03$ dollars

Therefore, Bobby's economic profits for the day is = $20\times0.03=0.60$ dollars

Hence, the answer is $0.60.

5 0

4 years ago

Please help Please thank you

Marina CMI [18]

Answer: C) The student made an error in step 3.

Step-by-step explanation:

When dividing by a negative while working with inequalities, you must "flip the sign." Thus, there is an error in step 3.

N.B. The answer could very well be interpreted as B), but I believe C) is the best and most defensible answer.

Hope it helps :) and let me know if you want me to elaborate.

8 0

3 years ago

Read 2 more answers

An animal shelter spends $2.35 per day for each cat and $5.50 per day to care for each dog. Pat noticed that the shelter spent $

Nadusha1986 [10]

Lets use the letter C to represent cats and D to represent dogs.

A) 2.35c + 5.50d = 89.50

For B, they give you numbers to plug into your equation.
c = 8
d= 14

B) 2.35(8) + 5.50(14) = 89.50
18.80 + 77.00 = 95.80

So what Pat said is incorrect because that would mean they spent more than 89.50.

Hope this helps! :)

6 0

4 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

5 0

4 years ago