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3 years ago

Let f be defined as shown. What is f^-1(8)?

Mathematics

1 answer:

Gnoma [55]3 years ago

4 0

Answer:

From the picture when the input of f(x) is 6 the output is 8

So it's just the reverse f^-1(8) when the input is 8 the output is 6

So f^-1(8) = 6

Hope this helps you

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Jerry has 8/9 gallon of paint. He uses 3/4 of it to paint his treehouse. How much paint is left?

mariarad [96]

.666 gallons, you multiply 8/9 by 3/4
and thats how you do it.

8 0

3 years ago

Fill in the boxes plz. Thanks

sesenic [268]

Answer:

$z = \frac{5}{8} \\$

Step-by-step explanation:

$9z + (7z-4)=6 \\ 9z + 7z - 4 = 6 \\ 16z = 6 + 4 \\ 16z = 10 \\ z = \frac{10}{16} \\ \\ z = \frac{5}{8}$

3 0

3 years ago

I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an

Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

$\mu = 0 - 5 = -5$

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

$\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}$

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1 - (-5)}{\sqrt{13}}$

$Z = \frac{6}{\sqrt{13}}$

$Z = 1.66$

$Z = 1.66$ has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0

3 years ago

P(t) = 2ť + 10<br> n(t) = 4<br> What’s the function (p+n) (t)?

Evgen [1.6K]

Answer:

$\boxed{\sf (p + n)(t) = 2t + 14}$

Given:

$\sf p(t) = 2t + 10 \\ \sf n(t) = 4$

To find:

$\sf (f + g)(x) = f(x) + g(x)$

Step-by-step explanation:

$\sf \implies(f + g)x = f(x) + g(x) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (2t + 10) + ( 4) \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 10 + 4 \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2t + 14$

7 0

3 years ago

Joylin win a $50 gift card for the local movie theater. She uses the entire amount on the card to purchase tickets and snacks fo

Alexeev081 [22]

Answer:

28$

Step-by-step explanation:

5 0

2 years ago

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