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3 years ago

Convert 30 pages/hour to pages/day.

Mathematics

1 answer:

liraira [26]3 years ago

8 0

30pages/hour| 1 day
| 24hours
So...
30\24= 1.25 pages/day

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A cafeteria offers oranges, apples , or bananas as it’s fruit option. Find the number of fruit and

Yuri [45]

Question:

A cafeteria offers oranges, apples, or bananas as its fruit option. It offers peas, green beans, or carrots as the vegetable option. Find the number of fruit and vegetable options. If the fruit and the vegetable are chosen at random. what is the probability of getting an orange and carrots? Is it likely or unlikely that a customer would get an orange and carrots?

Answer:

The probability of getting an orange and carrots is $\frac{1}{9}$

Step-by-step explanation:

The fruits offered in cafeteria = oranges, apples, or bananas.

The vegetables offered in cafeteria = peas, green beans, or carrots.

There are 3 fruits and 3 vegetables . Therefore the total possible number of outcomes is = $3 \cdot 3$ = 9

Now the probability of getting an orange and carrots = $\frac{1}{9}$

The possibility is very unlikely to happen

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4 years ago

What is the answer for this question

emmasim [6.3K]

The answer is 2/9. you just cross multiply then multiply straight across

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3 years ago

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In many cases the Law of Sines works perfectly well and returns the correct missing values in a non-right triangle. However, in

Agata [3.3K]

$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

Using the law of cosines,

$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$

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1 year ago

On a piece if paper graph y_>2x-3 Then determine which answer choice matches the graph you drew

alexandr1967 [171]

we have

$y\geq 2x-3$

Using a graph tool

see the attached figure

The solution of the inequality is the shaded area

therefore

the answer is the option B Graph C

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4 years ago

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Assoli18 [71]

Answer:

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Step-by-step explanation:

In this box-and-whisker plot, the first vertical line is the first quartile (-4), the second vertical line is the median (4), and the vertical line is the third quartile (6). The box contains the middle 50% of the data set.

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2 years ago