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andrey2020 [161]
4 years ago
11

Consider the following. x = 2 sin(y) , 0 ≤ y ≤ π, x = 0; about y = 4 (a) Set up an integral for the volume V of the solid obtain

ed by rotating the region bounded by the given curve about the specified axis.

Mathematics
1 answer:
azamat4 years ago
7 0

Answer:

V = 32π-4π^2

Step-by-step explanation:

See it in the pic.

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15

Step-by-step explanation:

We know that from e to f is 6 and that e to g is 21 , to find the answer we need to subtract the two numbers. Hope this helps!

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3 years ago
Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?
mafiozo [28]

Answer:

13x = 39

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2 years ago
What is the slope of the line that contains (-10,-8) (-4,40)
mart [117]

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y = 8x + 72

Step-by-step explanation:

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3 years ago
Is 0.¯8 a fraction??
Damm [24]
It's a decimal, but you can rewrite it as a fraction: -8/10 or -4/5 (simplified).
5 0
3 years ago
Read 2 more answers
What is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds $401$
salantis [7]

The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

According to the statement

We have a given that the maximum sum of the positive integers is 400.

And we have to find the value of n which is a maximum number of integers by which the value of sum become 400.

So, to find the value of the n we use the

A.P. Series'Summation formula

According to this,

S = n (n+1)/2

Here the value of s is 401

Then

S = n (n+1)/2

401 = n (n+1)/2

401*2 = n (n+1)

802 =n (n+1)

n (n+1) = 802

n^2 + n -802 =0

By the use of the Discriminant formula the

value of n becomes n = -28 and n = 27.

The negative value of n is neglected.

Therefore the value of n is 27.

So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.

Learn more about maximum number of integers here brainly.com/question/24295771

#SPJ4

7 0
2 years ago
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