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Ne4ueva [31]
4 years ago
11

Determine whether the random variable is discrete or continuous. In each​ case, state the possible values of the random variable

. ​(a) The number of people with blood type Upper A in a random sample of 27 people. ​(b) The square footage of a house. ​(a) Is the number of people with blood type Upper A in a random sample of 27 people discrete or​ continuous
Mathematics
1 answer:
xeze [42]4 years ago
5 0

Answer:

a) Discrete. Values 0,1,2,3,...,27

b) Continuous. Can be any real positive value.

Step-by-step explanation:

A random variable is discrete if it's values are natural, counting values. That is 0,1,2,3,4 etc

A random variable is continuous if it's values are real numbers, decimal. For example, 1, 2, 0.5, 0.22, etc.

(a) The number of people with blood type Upper A in a random sample of 27 people.

You cannot have 1.5 people with blood type Upper A, for example.

You can have 0,1,2,3,...,27.

This random variable is discrete.

​(b) The square footage of a house.

This square footage can be any real positive value, so it is continuous.

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Step-by-step explanation:

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3 years ago
Help Please (n^2-6n+3) and -4n
Rina8888 [55]
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3 years ago
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Step-by-step explanation:

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3 years ago
Determine (without solving the problem) an interval in which the solution of the given initial value problem is certain to exist
charle [14.2K]

Answer: t = - 5 ∈ I_{1} = ( -∞ , -4 )

Step-by-step explanation:

The standard form of O.D.E is written as :

y^{1} + p(t) = g(t)

Equation given :

(16-t^{2} )y^{1} + 9ty = 5t^{2} ,       y(-5) = 1

The first thing to do is to write the O.D.E in standard form , that is we will divide through by 16 - t^{2} , so we have

y^{1} + \frac{9ty}{16-t^{2}}=\frac{5t^{2}}{16-t^{2}}

With this , we can see that p(t) and g(t) are both continuous in the same domain. Therefore , the intervals are :

I_{1} = ( -∞ , -4 )

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I_{3} = ( 4 , -∞ )

recall that y(−5) = 1 , then t = -5

This means that :

t = - 5 ∈ I_{1} = ( -∞ , -4 )

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3 years ago
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