Question

Need help with part b. Thanks!

Answer 1

Answer:

$(x-4)^{2}$>0

$(x-4)^{2}$+4>0

so the function is always positive.

Step-by-step explanation:

As $(x-4)^{2}$ always positive, because when you square numbers you will get always a positive number.

So $(x-4)^{2}$+4>0, because the (+4) will not effect the answer as (x-4)^{2} will be positive.