Need help with part b. Thanks!

Mathematics

1 answer:

kiruha [24]4 years ago

5 0

Answer:

$(x-4)^{2}$ >0

$(x-4)^{2}$ +4>0

so the function is always positive.

Step-by-step explanation:

As $(x-4)^{2}$ always positive, because when you square numbers you will get always a positive number.

So $(x-4)^{2}$ +4>0, because the (+4) will not effect the answer as (x-4)^{2} will be positive.

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