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const2013 [10]
1 year ago
15

Suppose that each semester at a particular community college Manuel has to pay $1478 in tuition and $121 in fees.

Mathematics
1 answer:
Kamila [148]1 year ago
5 0

Answer:

Step-by-step explanation:

<em>Let x be time, in semesters, remaining before Manuel graduates</em>.  We find that Manuel's expenses are:

$1478/semester in tuition, and

$121/semester in fees

1.  <u>x semesters remaining:  fees</u>

  Remaining cost for fees, y, is the product of the fee times the number of semesters, x:

y =($121/semester)*x

y = ($121)*x

2.  <u>x semesters remaining:  tuition</u>

  Remaining cost, y, is the product of the tuition (times the number of semesters, x.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

3.  <u>x semesters remaining:  tuition and fees</u>

  Remaining cost, y, is the sum of the products of the tuition (times the number of semesters, and the fees (tix.  

y = ($1478/semester)*x + ($121/semester)*x

y = ($1599)*x

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iogann1982 [59]

Answer:

5in by 5in by 5in

Step-by-step explanation:

We are not told wat to find but we can as well find the dimension of the prism that will minimize its surface area.

Given

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Formula

V = w²h ..... 1

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h is the height of the prism

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Substitute eqn 3 into 2 as shown

S = 2w²+4wh

S = 2w²+4w(125/w²)

S = 2w²+500/w

To minimize the surface area, dS/dw = 0

dS/dw =4w-500/w²

0= 4w-500/w²

Multiply through by w²

0 = 4w³-500

-4w³ = -500

w³ = 500/4

w³ =125

w = cuberoot(125)

w = 5in

Get the height

125 =w²h

125 = 25h

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h = 5in

Hence the dimension of the prism is 5in by 5in by 5in

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2 years ago
The middle person in a row is the 18th, how many persons are in the row?
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Answer:

35

Step-by-step explanation:

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In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

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2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

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We have:

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The appropriate choice is
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