Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
Answer:140 meters
Step-by-step explanation:1km=100m, 1.4km times 100=140
At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12
the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12 ⇒⇒⇒⇒ multiplying the equation by 12
∴ 12y = -5x +95
</span>
Answer: only, domain, range, f(x)
Step-by-step explanation:
